Need help in parsing the below using reex

I am zero in regex and need help in parsing the value for key "access_token" from the below output.This will be later used in passing as variable for another function. So basically the regex should only fetch

我在正则表达式中为零,需要帮助从下面的输出中解析键“access_token”的值。这稍后将用作另一个函数的变量传递。所以基本上正则表达式只应该获取

eyJhbGciOiJIUzI1NiIsInR5cCI6IkpXVCJ9.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.qYID1b5lMjFhn7fTcSX5v6K6z2YpGJwAvE4gQfVrhxo

Here is the output of my Post output

这是我的Post输出的输出

{
    "access_token": "eyJhbGciOiJIUzI1NiIsInR5cCI6IkpXVCJ9.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.qYID1b5lMjFhn7fTcSX5v6K6z2YpGJwAvE4gQfVrhxo",
    "token_type": "bearer",
    "expires_in": 2999,
    "refresh_token": "65be41084c0b4adeaeec9725cb2e6240",
    "audience": "1412001",
    "displayName": "Lokesh",
    "userId": "testuser78",
    "rolesandpermission": "HELPDESK:9030,9000,9028,9027,9026,9025,9024,9023,9022,9021,9020,9019,9018,9013,9012,9011,9010,9009,9008,9007,9006,9005,9004,9003,9002,9001,9029",
    "resChannelID": "19",
    "Client": "FYC",
    "isAptClnt": "True",
    "scope": "apt:FYC env:PROD role:HELPDESK",
    ".issued": "Sun, 07 Oct 2018 12:17:29 GMT",
    ".expires": "Sun, 07 Oct 2018 13:07:29 GMT"
}

1 个解决方案

#1

Simple PCRE look like

简单的PCRE看起来像

\"access_token\":.\"(.+?)\"

And you will get your token in fast captured group You can practice with this regex on this website https://regex101.com/

并且您将在快速捕获的组中获得您的令牌您可以在此网站上使用此正则表达式练习https://regex101.com/

#1