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- How to subtract X days from a date using Java calendar? 9 answers
如何使用Java日历从日期中减去X天? 9个答案
I want to subtract n days from the current date in Java.
我想在Java中减去当前日期的n天。
How do I do that?
我怎么做?
5 个解决方案
#1
70
You don't have to use Calendar. You can just play with timestamps :
您不必使用日历。你可以玩时间戳:
Date d = initDate();//intialize your date to any date
Date dateBefore = new Date(d.getTime() - n * 24 * 3600 * 1000 l ); //Subtract n days
UPDATE DO NOT FORGET TO ADD "l" for long by the end of 1000.
更新不要忘记在1000年底之前添加“l”。
Please consider the below WARNING:
请考虑以下警告:
Adding 1000*60*60*24
milliseconds to a java date will once in a great while add zero days or two days to the original date in the circumstances of leap seconds, daylight savings time and the like. If you need to be 100% certain only one day is added, this solution is not the one to use.
在闰秒,夏令时等情况下,向java日期添加1000 * 60 * 60 * 24毫秒将在很长一段时间内添加零天或两天到原始日期。如果您需要100%确定只添加一天,则此解决方案不是使用的解决方案。
#2
48
this will subtract ten days of the current date (before Java 8):
这将减去当前日期的十天(在Java 8之前):
int x = -10;
Calendar cal = GregorianCalendar.getInstance();
cal.add( Calendar.DAY_OF_YEAR, x);
Date tenDaysAgo = cal.getTime();
If you're using Java 8 you can make use of the new Date & Time API (http://www.oracle.com/technetwork/articles/java/jf14-date-time-2125367.html):
如果您使用的是Java 8,则可以使用新的Date&Time API(http://www.oracle.com/technetwork/articles/java/jf14-date-time-2125367.html):
LocalDate tenDaysAgo = LocalDate.now().minusDays(10);
For converting the new to the old types and vice versa see: Converting between java.time.LocalDateTime and java.util.Date
要将新类型转换为旧类型,反之亦然,请参阅:在java.time.LocalDateTime和java.util.Date之间进行转换
#3
6
I found this perfect solution and may useful, You can directly get in format as you want:
我找到了这个完美的解决方案并且可能很有用,您可以根据需要直接获取格式:
Calendar cal = Calendar.getInstance();
cal.add(Calendar.DATE, -90); // I just want date before 90 days. you can give that you want.
SimpleDateFormat s = new SimpleDateFormat("yyyy-MM-dd"); // you can specify your format here...
Log.d("DATE","Date before 90 Days: " + s.format(new Date(cal.getTimeInMillis())));
Thanks.
#4
1
for future use find day of the week ,deduct day and display the deducted day using date.
public static void main(String args[]) throws ParseException {
String[] days = { "Sunday", "Monday", "Tuesday", "Wednesday",
"Thursday", "Friday", "Saturday" };
SimpleDateFormat format1 = new SimpleDateFormat("dd/MM/yyyy");
Date dt1 = format1.parse("20/10/2013");
Calendar c = Calendar.getInstance();
c.setTime(dt1);
int dayOfWeek = c.get(Calendar.DAY_OF_WEEK);
long diff = Calendar.getInstance().getTime().getTime() ;
System.out.println(dayOfWeek);
switch (dayOfWeek) {
case 6:
System.out.println(days[dayOfWeek - 1]);
break;
case 5:
System.out.println(days[dayOfWeek - 1]);
break;
case 4:
System.out.println(days[dayOfWeek - 1]);
break;
case 3:
System.out.println(days[dayOfWeek - 1]);
break;
case 2:
System.out.println(days[dayOfWeek - 1]);
break;
case 1:
System.out.println(days[dayOfWeek - 1]);
diff = diff -(dt1.getTime()- 3 );
long valuebefore = dt1.getTime();
long valueafetr = dt1.getTime()-2;
System.out.println("DATE IS befor subtraction :"+valuebefore);
System.out.println("DATE IS after subtraction :"+valueafetr);
long x= dt1.getTime()-(2 * 24 * 3600 * 1000);
System.out.println("Deducted date to find firday is - 2 days form Sunday :"+new Date((dt1.getTime()-(2*24*3600*1000))));
System.out.println("DIffrence from now on is :"+diff);
if(diff > 0) {
diff = diff / (1000 * 60 * 60 * 24);
System.out.println("Diff"+diff);
System.out.println("Date is Expired!"+(dt1.getTime() -(long)2));
}
break;
}
}
#5
-1
As @Houcem Berrayana say
正如@Houcem Berrayana所说
If you would like to use n>24
then you can use the code like:
如果你想使用n> 24,那么你可以使用如下代码:
Date dateBefore = new Date((d.getTime() - n * 24 * 3600 * 1000) - n * 24 * 3600 * 1000);
Suppose you want to find last 30 days date, then you'd use:
假设您要查找最近30天的日期,那么您将使用:
Date dateBefore = new Date((d.getTime() - 24 * 24 * 3600 * 1000) - 6 * 24 * 3600 * 1000);
#1
70
You don't have to use Calendar. You can just play with timestamps :
您不必使用日历。你可以玩时间戳:
Date d = initDate();//intialize your date to any date
Date dateBefore = new Date(d.getTime() - n * 24 * 3600 * 1000 l ); //Subtract n days
UPDATE DO NOT FORGET TO ADD "l" for long by the end of 1000.
更新不要忘记在1000年底之前添加“l”。
Please consider the below WARNING:
请考虑以下警告:
Adding 1000*60*60*24
milliseconds to a java date will once in a great while add zero days or two days to the original date in the circumstances of leap seconds, daylight savings time and the like. If you need to be 100% certain only one day is added, this solution is not the one to use.
在闰秒,夏令时等情况下,向java日期添加1000 * 60 * 60 * 24毫秒将在很长一段时间内添加零天或两天到原始日期。如果您需要100%确定只添加一天,则此解决方案不是使用的解决方案。
#2
48
this will subtract ten days of the current date (before Java 8):
这将减去当前日期的十天(在Java 8之前):
int x = -10;
Calendar cal = GregorianCalendar.getInstance();
cal.add( Calendar.DAY_OF_YEAR, x);
Date tenDaysAgo = cal.getTime();
If you're using Java 8 you can make use of the new Date & Time API (http://www.oracle.com/technetwork/articles/java/jf14-date-time-2125367.html):
如果您使用的是Java 8,则可以使用新的Date&Time API(http://www.oracle.com/technetwork/articles/java/jf14-date-time-2125367.html):
LocalDate tenDaysAgo = LocalDate.now().minusDays(10);
For converting the new to the old types and vice versa see: Converting between java.time.LocalDateTime and java.util.Date
要将新类型转换为旧类型,反之亦然,请参阅:在java.time.LocalDateTime和java.util.Date之间进行转换
#3
6
I found this perfect solution and may useful, You can directly get in format as you want:
我找到了这个完美的解决方案并且可能很有用,您可以根据需要直接获取格式:
Calendar cal = Calendar.getInstance();
cal.add(Calendar.DATE, -90); // I just want date before 90 days. you can give that you want.
SimpleDateFormat s = new SimpleDateFormat("yyyy-MM-dd"); // you can specify your format here...
Log.d("DATE","Date before 90 Days: " + s.format(new Date(cal.getTimeInMillis())));
Thanks.
#4
1
for future use find day of the week ,deduct day and display the deducted day using date.
public static void main(String args[]) throws ParseException {
String[] days = { "Sunday", "Monday", "Tuesday", "Wednesday",
"Thursday", "Friday", "Saturday" };
SimpleDateFormat format1 = new SimpleDateFormat("dd/MM/yyyy");
Date dt1 = format1.parse("20/10/2013");
Calendar c = Calendar.getInstance();
c.setTime(dt1);
int dayOfWeek = c.get(Calendar.DAY_OF_WEEK);
long diff = Calendar.getInstance().getTime().getTime() ;
System.out.println(dayOfWeek);
switch (dayOfWeek) {
case 6:
System.out.println(days[dayOfWeek - 1]);
break;
case 5:
System.out.println(days[dayOfWeek - 1]);
break;
case 4:
System.out.println(days[dayOfWeek - 1]);
break;
case 3:
System.out.println(days[dayOfWeek - 1]);
break;
case 2:
System.out.println(days[dayOfWeek - 1]);
break;
case 1:
System.out.println(days[dayOfWeek - 1]);
diff = diff -(dt1.getTime()- 3 );
long valuebefore = dt1.getTime();
long valueafetr = dt1.getTime()-2;
System.out.println("DATE IS befor subtraction :"+valuebefore);
System.out.println("DATE IS after subtraction :"+valueafetr);
long x= dt1.getTime()-(2 * 24 * 3600 * 1000);
System.out.println("Deducted date to find firday is - 2 days form Sunday :"+new Date((dt1.getTime()-(2*24*3600*1000))));
System.out.println("DIffrence from now on is :"+diff);
if(diff > 0) {
diff = diff / (1000 * 60 * 60 * 24);
System.out.println("Diff"+diff);
System.out.println("Date is Expired!"+(dt1.getTime() -(long)2));
}
break;
}
}
#5
-1
As @Houcem Berrayana say
正如@Houcem Berrayana所说
If you would like to use n>24
then you can use the code like:
如果你想使用n> 24,那么你可以使用如下代码:
Date dateBefore = new Date((d.getTime() - n * 24 * 3600 * 1000) - n * 24 * 3600 * 1000);
Suppose you want to find last 30 days date, then you'd use:
假设您要查找最近30天的日期,那么您将使用:
Date dateBefore = new Date((d.getTime() - 24 * 24 * 3600 * 1000) - 6 * 24 * 3600 * 1000);