Using SQL, I have 5 columns: ssn, lastname, firstname, RF and a flag field. I need to go through this table and where the 4 columns are equal to another row and the value of the flag field in that row is equal to 2050, then delete that 2050 record.
使用SQL,我有5列:ssn,lastname,firstname,RF和一个标志字段。我需要通过这个表,其中4列等于另一行,并且该行中的flag字段的值等于2050,然后删除该2050记录。
4 个解决方案
#1
delete from MyTable m
where flag = 2050
and exists (
select 1 from MyTable where
MyTable.ssn = m.ssn
and MyTable.lastname=m.lastname
and MyTable.firstname=m.firstname
and MyTable.RF=m.RF
and MyTable.flag <> 2050
)
#2
DELETE
T1
FROM
My_Table T1
INNER JOIN My_Table T2 ON
T2.ssn = T1.ssn AND
T2.last_name = T1.last_name AND
T2.first_name = T1.first_name AND
T2.RF_name = T1.RF_name AND
T2.flag <> T1.flag
WHERE
T1.flag = 2050
#3
delete from TableName as tn
where tn.flag = 2050 and
exists (select * from TableName as tn2 where tn.ssn = tn2.ssn
and tn.lastname = tn2.lastname and tn.firstname = tn2.firstname
and tn.rf = tn2.rf and tn2.flag <> 2050)
#4
delete from Table1
where flag = 2050
and exists (select *
from Table2
where ssn = Table1.ssn
and lastname = Table1.lastname
and firstname = Table1.firstname
and rf = Table1.rf
and flag <> 2050)
#1
delete from MyTable m
where flag = 2050
and exists (
select 1 from MyTable where
MyTable.ssn = m.ssn
and MyTable.lastname=m.lastname
and MyTable.firstname=m.firstname
and MyTable.RF=m.RF
and MyTable.flag <> 2050
)
#2
DELETE
T1
FROM
My_Table T1
INNER JOIN My_Table T2 ON
T2.ssn = T1.ssn AND
T2.last_name = T1.last_name AND
T2.first_name = T1.first_name AND
T2.RF_name = T1.RF_name AND
T2.flag <> T1.flag
WHERE
T1.flag = 2050
#3
delete from TableName as tn
where tn.flag = 2050 and
exists (select * from TableName as tn2 where tn.ssn = tn2.ssn
and tn.lastname = tn2.lastname and tn.firstname = tn2.firstname
and tn.rf = tn2.rf and tn2.flag <> 2050)
#4
delete from Table1
where flag = 2050
and exists (select *
from Table2
where ssn = Table1.ssn
and lastname = Table1.lastname
and firstname = Table1.firstname
and rf = Table1.rf
and flag <> 2050)