如何使用javascript获得没有$_GET参数的url路径?

If my current page is in this format...

如果我当前的页面是这种格式……

http://www.mydomain.com/folder/mypage.php?param=value

Is there an easy way to get this

有没有简单的方法来解决这个问题?

http://www.mydomain.com/folder/mypage.php

using javascript?

使用javascript ?

5 个解决方案

#1

Don't do this regex and splitting stuff. Use the browser's built-in URL parser.

不要做这个regex和分裂的事情。使用浏览器的内置URL解析器。

window.location.origin + window.location.pathname

And if you need to parse a URL that isn't the current page:

如果您需要解析一个不是当前页面的URL:

var url = document.createElement('a');
url.href = "http://www.example.com/some/path?name=value#anchor";
console.log(url.origin + url.pathname);

And to support IE (because IE doesn't have location.origin):

支持IE(因为IE没有location.origin):

location.protocol + '//' + location.host + location.pathname;

(Inspiration from https://*.com/a/6168370/711902)

(灵感来自https://*.com/a/6168370/711902)

#2

Try to use split like

尝试使用split like

var url = "http://www.mydomain.com/folder/mypage.php?param=value";
var url_array = url.split("?");
alert(url_array[0]);    //Alerts http://www.mydomain.com/folder/mypage.php

Even we have many parameters in the GET , the first segment will be the URL without GET parameters.

即使我们在GET中有很多参数，第一个段也是没有GET参数的URL。

This is DEMO

这是演示

#3

try this:

试试这个:

var url=document.location.href;
var mainurl=url.split("?");
alert(mainurl[0]);

#4

Try

试一试

var result = yourUrl.substring(0, yourUrl.indexOf('?'));

Working demo

演示工作

#5

var options = decodeURIComponent(window.location.search.slice(1))
     .split('&')
     .reduce(function _reduce (/*Object*/ a, /*String*/ b) {
     b = b.split('=');
     a[b[0]] = b[1];
     return a;
   }, {});

#1