XPath - 没有具有属性的子项时查找父项

I'm trying to find every reference to a node (report) that does not have a child node (property) with a specific attributes values.

我正在尝试查找对没有具有特定属性值的子节点（属性）的节点（报告）的每个引用。

My xml is:

我的xml是：

<report xmlns="http://www.eclipse.org/birt/2005/design">
<property name="comments">comment</property>
<property name="test">sdcs</property>
<property name="eventHandlerClass">sdcs</property>
</report>

and my XPath is:

我的XPath是：

/*[local-name()='report'][not(/*[local-name()='property'][@name='eventHandlerClass'])]

Problem is, it is returning the report when I'm looking for it to not return anything.

问题是，当我正在寻找不返回任何内容时，它会返回报告。

Any idea's on the best way to do this?

有什么想法是最好的方法吗？

2 个解决方案

#1

The problem is that your report contains a property that is not an evenHandlerClass. You want to say there is no such child, which could be done by counting such children and getting zero:

问题是您的报告包含的属性不是evenHandlerClass。你想说没有这样的孩子，这可以通过计算这些孩子并获得零来完成：

/*[local-name()='report'][count(*[(local-name()='property' and @name="eventHandlerClass")])=0]

#2

Please register a namespace before you execute your XPath.

请在执行XPath之前注册命名空间。

Using local-name() works but it produces very inelegant (and inefficient) XPath.

使用local-name（）可以工作，但它会产生非常不优雅（且效率低下）的XPath。

Supposing you have registered "http://www.eclipse.org/birt/2005/design" as birt:

假设您已将“http://www.eclipse.org/birt/2005/design”注册为birt：

//birt:report[not(birt:property[@name='eventHandlerClass'])]

If for some reason you cannot register a namespace, use (wrapped for legibility)

如果由于某种原因您无法注册命名空间，请使用（包装为易读性）

//*[
  local-name() = 'report' 
  and not(
    *[@local-name() = 'property' and @name='eventHandlerClass']
  )
]

#1