如何在MATLAB中创建正则间距数组?

How do I make an array that's defined with a start point, an end point, and a total array size? Something like an array that goes from 1 to 10 that's 20 elements long. For example, the array could look something like:

如何创建一个具有起点、终点和总数组大小的数组?比如一个从1到10的数组也就是20个元素长。例如，数组可以如下所示:

1 1.5 2 2.5 3 3.5 ...

3 个解决方案

#1

There are a couple of ways you can do this:

有几种方法可以做到这一点:

Using the colon operator:

使用冒号运算符:

startValue = 1;
endValue = 10;
nElements = 20;
stepSize = (endValue-startValue)/(nElements-1);
A = startValue:stepSize:endValue;

Using the linspace function (as suggested by Amro):

使用linspace函数(如银行所建议的):

startValue = 1;
endValue = 10;
nElements = 20;
A = linspace(startValue,endValue,nElements);

Keep in mind that the number of elements in the resulting arrays includes the end points. In the above examples, the difference between array element values will be 9/19, or a little less than 0.5 (unlike the sample array in the question).

记住，结果数组中的元素数量包括端点。在上面的示例中，数组元素值之间的差异将是9/19，或略小于0.5(与问题中的示例数组不同)。

#2

linspace generates linearly spaced vectors:

linspace生成线性间隔向量:

>>  A = linspace(1, 10, 20-1)
ans =
1 1.5 2 2.5 3 3.5 ... 9.5 10

#3

Simple one-liner!

简单的一行程序!

1:0.5:10;

Output:

输出:

1 1.5 2 2.5 ... 9 9.5 10

Note that this would be a 19-element vector, not 20.

注意这是一个19元向量，而不是20。

#1