Stuggling a little bit with the RegEx, I've got 4 codes in a string
使用RegEx进行一些处理,我在一个字符串中有4个代码
CODE4:CODE3:CODE2:CODE1
each code is optional apart from CODE1
除CODE1外,每个代码都是可选的
So I could have ab:bc:de:fg
所以我可以拥有ab:bc:de:fg
or
bc::fg
of
ab:::fg
In each case of the above CODE1 = fg dnd for the dear life of me I can't work out the RegEX
在上述CODE1 = fg dnd的每一种情况下,对于我的亲爱的生活,我无法解决RegEX问题
Would be easy to do as a standard string parse, but unforunatly because of buisness objects in needs to be done via regex :-( and return via a vb.net RegEX.matche,groups("Code1") fg (I hope that makes sense)
作为一个标准的字符串解析很容易做,但由于需要通过正则表达式完成商业对象,因此需要通过vge.net RegEX.matche,group(“Code1”)返回fg(我希望这样做)感)
Thanks in advance for any help
在此先感谢您的帮助
Ended up with a bit of RegEx that does the job, bit messy but it works
结束了一些RegEx来做这项工作,有点凌乱,但它的工作原理
(^(?<code1>[\w]*)$)|(^(?<code2>[\w]*):(?<code1>[\w]*)$)|(^(?<code3>[\w]*):(?<code2>[\w]*):(?<code1>[\w]*)$)|(^(?<code4>[\w]*):(?<code3>[\w]*):(?<code2>[\w]*):(?<code1>[\w]*)$)
Ta all
3 个解决方案
#1
There's no need to use a regular expression here.
这里不需要使用正则表达式。
I don't know what language you're using, but split the string on ':' and you'll have an array of codes.
我不知道你正在使用什么语言,但是将字符串拆分为':',你将拥有一系列代码。
If you really just want to validate whether a string is valid for this then
如果你真的只想验证字符串是否对此有效
/(\w*:){0,3}\w+/
matches your description and the few examples you've given.
符合您的描述和您给出的几个示例。
#2
I'm not sure why you have to match the codes right to left. Simply use a regular expression to pick apart the string:
我不确定为什么你必须从右到左匹配代码。只需使用正则表达式来分离字符串:
/(.*):(.*):(.*):(.+)/
and then you have CODE1 in $4, CODE2 in $3, CODE3 in $2, CODE4 in $1.
然后你有4美元的CODE1,3美元的CODE2,2美元的CODE3,1美元的CODE4。
#3
(CODE1)?:(CODE2)?:(CODE3)?:CODE4 would work - if the leading : don't matter. Otherwise, if you can't have leading colons, enumerate:
(CODE1)?:( CODE2)?:( CODE3)?:CODE4会起作用 - 如果领先:无所谓。否则,如果您不能拥有前导冒号,请枚举:
(CODE1:(CODE2)?:(CODE3)?:|CODE2:(CODE3)?:|CODE3)?CODE4
There's nothing special about the fact that the right-most part is mandatory, and the left-most parts aren't.
没有什么特别的事实,最右边的部分是强制性的,而最左边的部分则不是。
#1
There's no need to use a regular expression here.
这里不需要使用正则表达式。
I don't know what language you're using, but split the string on ':' and you'll have an array of codes.
我不知道你正在使用什么语言,但是将字符串拆分为':',你将拥有一系列代码。
If you really just want to validate whether a string is valid for this then
如果你真的只想验证字符串是否对此有效
/(\w*:){0,3}\w+/
matches your description and the few examples you've given.
符合您的描述和您给出的几个示例。
#2
I'm not sure why you have to match the codes right to left. Simply use a regular expression to pick apart the string:
我不确定为什么你必须从右到左匹配代码。只需使用正则表达式来分离字符串:
/(.*):(.*):(.*):(.+)/
and then you have CODE1 in $4, CODE2 in $3, CODE3 in $2, CODE4 in $1.
然后你有4美元的CODE1,3美元的CODE2,2美元的CODE3,1美元的CODE4。
#3
(CODE1)?:(CODE2)?:(CODE3)?:CODE4 would work - if the leading : don't matter. Otherwise, if you can't have leading colons, enumerate:
(CODE1)?:( CODE2)?:( CODE3)?:CODE4会起作用 - 如果领先:无所谓。否则,如果您不能拥有前导冒号,请枚举:
(CODE1:(CODE2)?:(CODE3)?:|CODE2:(CODE3)?:|CODE3)?CODE4
There's nothing special about the fact that the right-most part is mandatory, and the left-most parts aren't.
没有什么特别的事实,最右边的部分是强制性的,而最左边的部分则不是。