想要在某个单词后拆分一个字符串？

Here is my code:

这是我的代码:

var url="https://muijal-ip-dev-ed.my.salesforce.com/apexpages/setup/viewApexPage.apexp?id=066415642TPaE";

In this string i need only

在这个字符串中我只需要

url="https://muijal-ip-dev-ed.my.salesforce.com/"

i need string upto "com/" rest of the string should be removed.

我需要字符串upto“com /”应该删除字符串的其余部分。

5 个解决方案

#1

In modern browsers you can use URL()

在现代浏览器中,您可以使用URL()

var url=new URL("https://muijal-ip-dev-ed.my.salesforce.com/apexpages/setup/viewApexPage.apexp?id=066415642TPaE");

console.log(url.origin)

For unsupported browsers use regex

对于不受支持的浏览器,请使用正则表达式

#2

use javascript split

使用javascript拆分

url = url.split(".com");
url = url[0] + ".com";

That should leave you with the wanted string if the Url is well formed.

如果Url格式正确,那么应该给你留下想要的字符串。

#3

You can use locate then substr like this:

你可以像这样使用locate然后substr:

var url = url.substr(0, url.locate(".com"));

locate returns you the index of the string searched for and then substr will cut from the beginning until that index~

locate返回搜索到的字符串的索引,然后substr将从开头剪切到该索引〜

#4

Substring function should handle that nicely:

子串函数应该很好地处理:

function clipUrl(str, to, include) {
  if (include === void 0) {
    include = false;
  }
  return str.substr(0, str.indexOf(to) + (include ? to.length : 0));
}
console.log(clipUrl("https://muijal-ip-dev-ed.my.salesforce.com/apexpages/setup/viewApexPage.apexp?id=066415642TPaE", ".com", true));

#5

If the URL API (as suggested by another answer) isn't available you can reliably use properties of the HTMLAnchorElement interface as a workaround if you want to avoid using regular expressions.

如果URL API(由另一个答案建议)不可用,则可以可靠地使用HTMLAnchorElement接口的属性作为解决方法,以避免使用正则表达式。

var a = document.createElement('a');
a.href = 'https://muijal-ip-dev-ed.my.salesforce.com/apexpages/setup/viewApexPage.apexp?id=066415642TPaE';
console.log(a.protocol + '//' + a.hostname);

#1