函数内未定义变量,函数内无法连接MySQL $connection

时间:2022-04-11 20:25:54

I have a code that works when I use it on a page but Im trying to make this a function. I cant get it to work, it seems like the variables $customer and $system arent being sent through to the code. Even if I type it in Raw. Any idea whats wrong? $Customer is the name of the customer, $system can be 'Source' or 'Target'.

当我在一个页面上使用它的时候,我有一个代码,但是我想让它成为一个函数。我无法让它工作,似乎$customer和$system变量并没有被发送到代码中。即使我输入的是Raw格式。知道什么是错误的吗?$Customer是客户的名称,$system可以是“Source”或“Target”。

function status_total($customer, $system){
        $sql_customer       = "SELECT * FROM `Customer` WHERE Cust_Name = '$customer' LIMIT 0,1";
        $customer_selection = mysqli_query($conn,$sql_customer);
        $customer_row       = mysqli_fetch_assoc($customer_selection);
        $env_lines          = $customer_row["Env_Lines"];
        $cust_id            = $customer_row["Cust_ID"];
        $sql_last_records   = "SELECT * FROM $system WHERE Cust_ID = $cust_id ORDER BY Time DESC LIMIT $env_lines";
        $record_selection   = mysqli_query($conn, $sql_last_records);               

        $result = mysqli_fetch_all($record_selection, MYSQLI_ASSOC);
        $states = array_column($result, "Stat");

        if($states == array_fill(0, count($states), "Run")) {
            echo "Success";
        } else 
            echo "Fail";

    }

https://gist.github.com/R2D2-05/78d81566e4bf0eafd1fa

https://gist.github.com/R2D2-05/78d81566e4bf0eafd1fa

1 个解决方案

#1


4  

The problem with your code is $conn variable which is treated a local variable inside a function. You should:

代码的问题是$conn变量,它处理函数内的局部变量。你应该:

function status_total($customer, $system){
        global $conn;

        $sql_customer       = "SELECT * FROM `Customer` WHERE Cust_Name = '$customer' LIMIT 0,1";
        $customer_selection = mysqli_query($conn,$sql_customer);
        $customer_row       = mysqli_fetch_assoc($customer_selection);
        $env_lines          = $customer_row["Env_Lines"];
        $cust_id            = $customer_row["Cust_ID"];
        $sql_last_records   = "SELECT * FROM $system WHERE Cust_ID = $cust_id ORDER BY Time DESC LIMIT $env_lines";
        $record_selection   = mysqli_query($conn, $sql_last_records);               

        $result = mysqli_fetch_all($record_selection, MYSQLI_ASSOC);
        $states = array_column($result, "Stat");

        if($states == array_fill(0, count($states), "Run")) {
            echo "Success";
        } else 
            echo "Fail";

    }

Or you can also pass the $conn through the function, so change the function's definition to:

或者您也可以通过函数传递$conn,因此将函数的定义更改为:

function status_total($conn, $customer, $system){...}

#1


4  

The problem with your code is $conn variable which is treated a local variable inside a function. You should:

代码的问题是$conn变量,它处理函数内的局部变量。你应该:

function status_total($customer, $system){
        global $conn;

        $sql_customer       = "SELECT * FROM `Customer` WHERE Cust_Name = '$customer' LIMIT 0,1";
        $customer_selection = mysqli_query($conn,$sql_customer);
        $customer_row       = mysqli_fetch_assoc($customer_selection);
        $env_lines          = $customer_row["Env_Lines"];
        $cust_id            = $customer_row["Cust_ID"];
        $sql_last_records   = "SELECT * FROM $system WHERE Cust_ID = $cust_id ORDER BY Time DESC LIMIT $env_lines";
        $record_selection   = mysqli_query($conn, $sql_last_records);               

        $result = mysqli_fetch_all($record_selection, MYSQLI_ASSOC);
        $states = array_column($result, "Stat");

        if($states == array_fill(0, count($states), "Run")) {
            echo "Success";
        } else 
            echo "Fail";

    }

Or you can also pass the $conn through the function, so change the function's definition to:

或者您也可以通过函数传递$conn,因此将函数的定义更改为:

function status_total($conn, $customer, $system){...}