在javascript中以数组的形式删除对象。

I want to remove object from array that matches the id from array, like this one

我想从数组中移除对象，它与数组中的id相匹配，比如这个。

var report = [{ id:1, title: "title 1"},{ id:2, title: "title 2"},{ id:3, title: "title 3"},{ id:4, title: "title 4"},{ id:5, title: "title 5"}];
var array = [1,2,3];

I just want to remove an object that matches in an array. The result that I expected is like

我只是想要移除一个数组中匹配的对象。我期望的结果是。

var report = [{ id:4, title: "title 4"},{ id:5, title: "title 5"}];

I have used .splice. method on .forEach but it seems doesn't work so well.

我用.splice。方法。foreach，但它似乎不太好用。

Any help will be appreciated :)

如有任何帮助，我们将不胜感激:

3 个解决方案

#1

You can use filter() and indexOf()

您可以使用filter()和indexOf()

var report = [{ id:1, title: "title 1"},{ id:2, title: "title 2"},{ id:3, title: "title 3"},{ id:4, title: "title 4"},{ id:5, title: "title 5"}];
var array = [1,2,3];

var result = report.filter(function(e) {
  return array.indexOf(e.id) == -1;
})

console.log(result)

#2

var report = [{ id:1, title: "title 1"},{ id:2, title: "title 2"},{ id:3, title:"title 3"},{ id:4, title: "title 4"},{ id:5, title: "title 5"}];
var array = [1,2,3];

var newReport = report.filter(function(item){
  return array.indexOf(item.id) == -1;
})

#3

A solution with .splice() (but without .forEach())

一个带.splice()的解决方案(但是没有。foreach ())

var report = [
  { id: 1, title: "title 1" },
  { id: 2, title: "title 2" },
  { id: 3, title: "title 3" },
  { id: 4, title: "title 4" },
  { id: 5, title: "title 5" }
];
var array = [1, 2, 3];

// "walk" backwards to circumvent the problem of the changing length because of .splice()
for (var i = (report.length - 1); i >= 0; i--) {
  if (array.indexOf(report[i].id) > -1) {
    report.splice(i, 1);
  }
}

console.log(report);

#1