将uint8_t 转化为unsigned 类型
使用一元运算符+(和- 运算符对应)
测试代码如下
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#include <cstdint>
#include <iostream>
#include <typeinfo>
int main()
{
std::uint8_t uint8_num = 10;
std::cout << "uint8_t num is " << uint8_num << std::endl; //无法打印
std::cout << "after cast to unsigned, uint8_t num is " << unsigned(uint8_num) << std::endl; //能正常打印
std::cout << "with a unary + operator, uint8_t num is " << +uint8_num << std::endl; //能正常打印
std::cout << "type of '+uint8_num' is " << typeid(+uint8_num).name() << std::endl;
return 0;
}
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运行结果如下
可见使用+运算符的原理也是进行类型转换(把uint8_t 转为 int)
补充知识：C 语言printf打印各种数据类型的方法(u8/s8/u16/s16.../u64/double/float)(全)
首先必须知道u8,s8等数据类型的定义：
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typedef signed char s8;
typedef unsigned char u8;
typedef signed short s16;
typedef unsigned short u16;
typedef signed int s32;
typedef unsigned int u32;
typedef signed long long s64;
typedef unsigned long long u64;
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与体系结构相关的，定义在include/linux/type.h文件中：
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/* bsd */
typedef unsigned char u_char;
typedef unsigned short u_short;
typedef unsigned int u_int;
typedef unsigned long u_long;
/* sysv */
typedef unsigned char unchar;
typedef unsigned short ushort;
typedef unsigned int uint;
typedef unsigned long ulong;
#ifndef __BIT_TYPES_DEFINED__
#define __BIT_TYPES_DEFINED__
typedef __u8 u_int8_t;
typedef __s8 int8_t;
typedef __u16 u_int16_t;
typedef __s16 int16_t;
typedef __u32 u_int32_t;
typedef __s32 int32_t;
#endif /* !(__BIT_TYPES_DEFINED__) */
typedef __u8 uint8_t;
typedef __u16 uint16_t;
typedef __u32 uint32_t;
#if defined(__GNUC__)
typedef __u64 uint64_t;
typedef __u64 u_int64_t;
typedef __s64 int64_t;
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对于各种数据类型的打印方式总结如下如下：
| 数据类型 | 打印格式 |
|---|---|
| u8 | %d |
| s8 | %d |
| u16 | %d or %hu |
| s16 | %d or %hd |
| u32 | %u |
| s32 | %d |
| u64 | %llu |
| s64 | %lld |
| int | %d |
| unsigned int | %u |
| short int | %d or %hd |
| long | %ld |
| unsigned long | %lu |
| long long | %lld |
| unsigned long long | %llu |
| char | %c |
| char * | %s |
| bool (#define stdbool.h) | %d |
| unsigned int/int------>十六进制 | %0x |
| unsigned long/long---->十六进制 | %0lx |
| long long/unsigned long long ----->十六进制 | %0llx |
| unsigned int/int------>八进制 | %0o |
| unsigned long/long---->八进制 | %0lo |
| long long/unsigned long long ----->八进制 | %0llo |
| float | %f |
| double | %f or %lf |
| 科学技术类型(必须转化为double类型) | %e |
| 限制输出字段宽度 | %x.yf (x:整数长度,y:小数点长度) |
待解问题，在linux kernel里面也有使用bool来定义变量，查看code，定义如下：
typedef _Bool bool;
但是并没有真正找到具体定义在何处，待解。
下面是stdbool.h的source code：
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#define _STDBOOL_H
#ifndef __cplusplus
#define bool _Bool
#define true 1
#define false 0
#else /* __cplusplus */
/* Supporting _Bool in C++ is a GCC extension. */
#define _Bool bool
#if __cplusplus < 201103L
/* Defining these macros in C++98 is a GCC extension. */
#define bool bool
#define false false
#define true true
#endif
#endif /* __cplusplus */
/* Signal that all the definitions are present. */
#define __bool_true_false_are_defined 1
#endif /* stdbool.h */
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也大致解释了linux kernel bool type了。
以上这篇c++ 解决无法打印uint8_t 类型变量的问题就是小编分享给大家的全部内容了，希望能给大家一个参考，也希望大家多多支持服务器之家。
原文链接：https://blog.csdn.net/feidaji/article/details/85088819