Prototype 1.6.1和jquery 1.7.2的Ajax Post请求方法对比

//使用Prototype 1.6.1的ajax请求方法
function prototypeRequest() {
	new Ajax.Request('servlet/SendInjunction', {
				method : 'post',
				parameters : {
					company : 'example',
					type : 'onePosition'
				},
				onSuccess : function(response) {
					if (200 == response.status) {
						alert("Call is success");
						var content = response.responseText;
						var result = response.responseText.evalJSON();
						alert('content:' + content);
						alert('result.code:' + result.code);
					}
				},
				onFailure : function failureFunc(response) {
					alert("Call is failed");
				}
			});
}
/*
 * function successFunc(response) { if (200 == response.status) { alert("Call is
 * success"); var content = response.responseText; alert('content:'+content); } }
 * 
 * function failureFunc(response) { alert("Call is failed"); }
 */


//jquery 1.7.2的ajax请求方法
function jqueryRequest() {
	$.post('servlet/SendInjunction', {
				company : 'example',
				type : 'onePosition'
			}, function(data) {
				alert('data:' + data);
				alert(data.code);
			}, "json");
}

Servlet部分：

		String company = request.getParameter("company");
		System.out.println("companyP:"+company);
		HashMap hm=new HashMap();
		hm.put("companyP",company);
		hm.put("code",10000);
		JsonUtil.responseJsonObject(response, hm);

responseJsonObject:

	public static void responseJsonObject(HttpServletResponse response, Object obj) throws IOException{ 
		String json;
		PrintWriter out = null;
		try {
			json = JSONUtil.serialize(obj);
			//System.out.println("json:" + json);
			out = response.getWriter();
			out.print(json);
			out.flush();		
		} catch (JSONException e) {
			e.printStackTrace();
		}finally{
			if(out != null){
				out.close();
			}
		}
	}

用到了googlecode中的jsonplugin.jar