I have an array of rectangle objects which I've populated in an array rectangles
. Each rectangle has various properties, texture, position and so on. How can I sort the rectangles array so that the objects are arranged in ascending order of the x position. The x position property is accessible in the following way, for example.
我有一个矩形对象数组我在数组矩形中填充了这些对象。每个矩形都有不同的属性、纹理、位置等等。如何对矩形数组进行排序,使对象按x位置的升序排列。例如,可以通过以下方式访问x position属性。
rectangles[0].sprite.position.x
I am open to a solution to this problem that is faster or more effective than sorting.
我对这个问题的解决方案持开放态度,它比排序更快或更有效。
2 个解决方案
#1
3
Use sort()
method. let sortedRectangles = rectangles.sort {$0.sprite.position.x < $1.sprite.position.x}
使用sort()方法。让sortedRectangles =矩形。{ sprite.position 0.美元。x < 1.美元sprite.position.x }
#2
2
rectangles
is an array with range (x,y)
:
矩形是一个范围为(x,y)的数组:
func backwardsX(s1: (CGFloat,CGFloat), _ s2: (CGFloat,CGFloat)) -> Bool {
return s1.0 > s2.0
}
let result = rectangles.sort(backwardsX)
Even in one line:
即使在一行:
let result = rectangles.sort( { s1, s2 in return s1.0 > s2.0 } )
or
或
let result = rectangles.sort( { $0.0 > $1.0 } )
#1
3
Use sort()
method. let sortedRectangles = rectangles.sort {$0.sprite.position.x < $1.sprite.position.x}
使用sort()方法。让sortedRectangles =矩形。{ sprite.position 0.美元。x < 1.美元sprite.position.x }
#2
2
rectangles
is an array with range (x,y)
:
矩形是一个范围为(x,y)的数组:
func backwardsX(s1: (CGFloat,CGFloat), _ s2: (CGFloat,CGFloat)) -> Bool {
return s1.0 > s2.0
}
let result = rectangles.sort(backwardsX)
Even in one line:
即使在一行:
let result = rectangles.sort( { s1, s2 in return s1.0 > s2.0 } )
or
或
let result = rectangles.sort( { $0.0 > $1.0 } )