how can I query to get the specific message from either inbox or outbox given that I have its _id --> i.e. message id.
如果我有_id - > ie消息ID,我如何查询从收件箱或发件箱中获取特定消息。
this is my route
get("/getSpecificMessage/{Message_id}", (req, res) => {..}
what I can do is find all the buyer/dealer and then go through inbox/outbox of all the buyer/dealer and then find the message with _id i.e. message_id --> can I do it better then that.
我能做的就是找到所有买家/经销商,然后通过所有买家/经销商的收件箱/发件箱,然后找到带有_id的消息,即message_id - >我能做得更好吗。
{
"_id" : ObjectId("5b8f0f4de276dd1e0ff083e1"),
"address" : {
"proper_address" : "sarai kale khan",
"lat" : 28.58894,
"long" : "77.25692"
},
"name" : "prashant",
"password" : "jfalksdjlk;jasdl",
"email" : "prashant@gmail.com",
"inbox" : [
{
"_id" : ObjectId("5b8f0f4de276dd1e0ff083e4"),
"date" : ISODate("2018-09-04T23:03:41.627Z"),
"from" : "1@1.com",
"message" : "message_1"
},
{
"_id" : ObjectId("5b8f0f4de276dd1e0ff083e3"),
"date" : ISODate("2018-09-04T23:03:41.627Z"),
"from" : "2@2.com",
"message" : "message_2"
},
{
"_id" : ObjectId("5b8f0f4de276dd1e0ff083e2"),
"date" : ISODate("2018-09-04T23:03:41.627Z"),
"from" : "3@3.com",
"message" : "message_3"
}
],
"outbox" : [
{
"_id" : ObjectId("5b8f0f4de276dd1e0ff083e7"),
"date" : ISODate("2018-09-04T23:03:41.627Z"),
"to" : "1@1.com",
"message" : "message_4"
},
{
"_id" : ObjectId("5b8f0f4de276dd1e0ff083e6"),
"date" : ISODate("2018-09-04T23:03:41.627Z"),
"to" : "1@1.com",
"message" : "message_5"
},
{
"_id" : ObjectId("5b8f0f4de276dd1e0ff083e5"),
"date" : ISODate("2018-09-04T23:03:41.627Z"),
"to" : "1@1.com",
"message" : "message_6"
}
],
"__v" : 0
}
{
"_id" : ObjectId("5b8f0f4de276dd1e0ff083e8"),
"address" : {
"proper_address" : "najafgarah",
"lat" : 28.58894,
"long" : "77.25692"
},
"name" : "rahul",
"password" : "jkalsjdflasdl",
"email" : "rahul@gmail.com",
"inbox" : [
{
"_id" : ObjectId("5b8f0f4de276dd1e0ff083eb"),
"date" : ISODate("2018-09-04T23:03:41.639Z"),
"from" : "1@1.com",
"message" : "message_1"
},
{
"_id" : ObjectId("5b8f0f4de276dd1e0ff083ea"),
"date" : ISODate("2018-09-04T23:03:41.639Z"),
"from" : "2@2.com",
"message" : "message_2"
},
{
"_id" : ObjectId("5b8f0f4de276dd1e0ff083e9"),
"date" : ISODate("2018-09-04T23:03:41.639Z"),
"from" : "3@3.com",
"message" : "message_3"
}
],
"outbox" : [
{
"_id" : ObjectId("5b8f0f4de276dd1e0ff083ee"),
"date" : ISODate("2018-09-04T23:03:41.639Z"),
"to" : "1@1.com",
"message" : "message_4"
},
{
"_id" : ObjectId("5b8f0f4de276dd1e0ff083ed"),
"date" : ISODate("2018-09-04T23:03:41.639Z"),
"to" : "1@1.com",
"message" : "message_5"
},
{
"_id" : ObjectId("5b8f0f4de276dd1e0ff083ec"),
"date" : ISODate("2018-09-04T23:03:41.639Z"),
"to" : "1@1.com",
"message" : "message_6"
}
],
"__v" : 0
}
So if I have the _id = 5b8f0f4de276dd1e0ff083ea and I want
所以,如果我有_id = 5b8f0f4de276dd1e0ff083ea,我想要
{
"_id" : ObjectId("5b8f0f4de276dd1e0ff083ea"),
"date" : ISODate("2018-09-04T23:03:41.639Z"),
"from" : "2@2.com",
"message" : "message_2"
}
2 个解决方案
#1
1
I am not sure if you want it using MongoDB scripts or your app language (Nodejs if I am mistaken)
我不确定您是否希望使用MongoDB脚本或您的应用程序语言(如果我弄错了Nodejs)
This is how it works on Mongo Shell Script
这是它在Mongo Shell Script上的工作原理
db.MODEL.find( { _id: DOCUMENT_ID },
{ inbox: { $elemMatch: { _id: MESSAGE_ID } } } )
文档在这里
If this is not what you want, please update your post and add which language/framework you are using
如果这不是您想要的,请更新您的帖子并添加您正在使用的语言/框架
#2
1
This is what you could do using the aggregation framework:
这是您可以使用聚合框架执行的操作:
var oId = new ObjectId("5b8f0f4de276dd1e0ff083ea");
db.collection.aggregate({
$match: { // can be skipped but I'd personally keep it because this will use an index on "input._id"/"output._id" (if there is one) to filter out irrelevant documents
$or: [
{ "inbox": { $elemMatch: { "_id": oId } } },
{ "outbox": { $elemMatch: { "_id": oId } } },
]
}
}, {
$project: {
result: {
$concatArrays: [
{ $filter: { "input": "$inbox", "cond": { $eq: [ "$$this._id", oId ] } } },
{ $filter: { "input": "$outbox", "cond": { $eq: [ "$$this._id", oId ] } } }
]
}
}
}, {
$unwind: "$result" // flatten the result array
}, {
$replaceRoot: {
"newRoot": "$result" // move "result" contents all the way up
}
})
#1
1
I am not sure if you want it using MongoDB scripts or your app language (Nodejs if I am mistaken)
我不确定您是否希望使用MongoDB脚本或您的应用程序语言(如果我弄错了Nodejs)
This is how it works on Mongo Shell Script
这是它在Mongo Shell Script上的工作原理
db.MODEL.find( { _id: DOCUMENT_ID },
{ inbox: { $elemMatch: { _id: MESSAGE_ID } } } )
文档在这里
If this is not what you want, please update your post and add which language/framework you are using
如果这不是您想要的,请更新您的帖子并添加您正在使用的语言/框架
#2
1
This is what you could do using the aggregation framework:
这是您可以使用聚合框架执行的操作:
var oId = new ObjectId("5b8f0f4de276dd1e0ff083ea");
db.collection.aggregate({
$match: { // can be skipped but I'd personally keep it because this will use an index on "input._id"/"output._id" (if there is one) to filter out irrelevant documents
$or: [
{ "inbox": { $elemMatch: { "_id": oId } } },
{ "outbox": { $elemMatch: { "_id": oId } } },
]
}
}, {
$project: {
result: {
$concatArrays: [
{ $filter: { "input": "$inbox", "cond": { $eq: [ "$$this._id", oId ] } } },
{ $filter: { "input": "$outbox", "cond": { $eq: [ "$$this._id", oId ] } } }
]
}
}
}, {
$unwind: "$result" // flatten the result array
}, {
$replaceRoot: {
"newRoot": "$result" // move "result" contents all the way up
}
})