我将如何创建一个重定向到launch.php的mod_rewrite？i = / the / url / that / they / want？

So if the user types mydomain.com/dashboard, the document the server actually sends them is /launch.php?i=/dashboard.

因此,如果用户键入mydomain.com/dashboard,则服务器实际发送的文档为/launch.php?i=/dashboard。

The one caveat is that I would like to leave requests for

一个警告是,我想留下请求

/flags
/people
/posters
/css
/icons
/images
/libraries
/patterns

alone, and they should request the actual folder.

单独,他们应该请求实际的文件夹。

How would I create such a mod_rewrite?

我该如何创建这样的mod_rewrite?

1 个解决方案

#1

This is the .htaccess file for the CakePHP Framework.

这是CakePHP框架的.htaccess文件。

Please replace the index.php and ?url= to fit your needs.

请替换index.php和?url =以满足您的需求。

<IfModule mod_rewrite.c>
    RewriteEngine On
    RewriteCond %{REQUEST_FILENAME} !-d
    RewriteCond %{REQUEST_FILENAME} !-f
    RewriteRule ^(.*)$ index.php?url=$1 [QSA,L]
</IfModule>

The "!-d" tells Apache to follow existing folders and "!-f" to follow existing files.

“!-d”告诉Apache遵循现有文件夹,“! - f”跟随现有文件。

Everything else is channelled through index.php

其他一切都是通过index.php引导的

As suggested in a comment, you have to be aware that if it's not working it could be because mod_rewrite is not enabled and you'll not get an error stating that fact, you'll probably only have a HTTP 404.

正如评论中所建议的那样,你必须要知道,如果它不起作用,可能是因为mod_rewrite没有启用,你不会得到一个错误说明这个事实,你可能只有一个HTTP 404。

#1