Jmeter正则表达式提取器没有获得价值

I have a problem. I am using Regular Expression Extractor in Jmeter. I have two regex.

我有个问题。我在Jmeter中使用正则表达式提取器。我有两个正则表达式。

I can get the value from this.

我可以从中获得价值。

Reference Name: as_fid_addtobasket

Regular Expression: <input type="hidden" name="as_fid" value="(.+?)" />

Template: $1$

But i can't get the value from this one.

但我无法从这一点获得价值。

> Reference Name: DynamicTempOrderProductGuid 
> 
> Regular Expression: <input data-val="true" data-val-required="The
> TempOrderProductGuid field is required."
> id="OrderProducts_1__TempOrderProductGuid"
> name="OrderProducts[1].TempOrderProductGuid" type="hidden"
> value="(.+?)" />
> 
> Template: $1$
> >

Here is my result. The second one doesn't get the value. Where is the thing i missed?

这是我的结果。第二个没有得到价值。我错过了哪里?

POST data: OrderProducts.index=1&OrderProducts%5B1%5D.TempOrderProductGuid=%24%7BDynamicTempOrderProductGuid%7D&OrderProducts%5B1%5D.Count=1&OrderProducts%5B1%5D.ReceiverModel.OrderReceiver.NameRec=Test+ama%C3%A7l%C4%B1d%C4%B1r.+L%C3%BCtfen+dikkate+almay%C4%B1n%C4%B1z&OrderProducts%5B1%5D.ReceiverModel.OrderReceiver.PhoneRec=05352233285&OrderProducts%5B1%5D.ReceiverModel.OrderReceiver.OSSendingReason=&OrderProducts%5B1%5D.ReceiverModel.OrderReceiver.OSReceiverAddressType=&OrderProducts%5B1%5D.ReceiverModel.OrderReceiver.CompanyNameRec=&OrderProducts%5B1%5D.ReceiverModel.OrderReceiver.AddressLineRec=Test+ama%C3%A7l%C4%B1d%C4%B1r.+L%C3%BCtfen+dikkate+almay%C4%B1n%C4%B1z&OrderProducts%5B1%5D.ProductCode=se213&OrderProducts%5B1%5D.TempOrderProductGuid=%24%7Btokentoken%7D&totalProducts=1&as_fid=efWZ0i4RGLmC2nBWk%2FA1

POST数据:OrderProducts.index = 1&OrderProducts%5B1%5D.TempOrderProductGuid =%24%7BDynamicTempOrderProductGuid%7D&OrderProducts%5B1%5D.Count = 1&OrderProducts%5B1%5D.ReceiverModel.OrderReceiver.NameRec = Test + ama%C3%A7l%C4% B1D%C4%B1R。+ L%C3%BCtfen + dikkate +爱尔美%C4%B1n的%C4%B1z&OrderProducts%5B1%5D.ReceiverModel.OrderReceiver.PhoneRec = 05352233285&OrderProducts%5B1%5D.ReceiverModel.OrderReceiver.OSSendingReason =&OrderProducts%5B1 %5D.ReceiverModel.OrderReceiver.OSReceiverAddressType =&OrderProducts%5B1%5D.ReceiverModel.OrderReceiver.CompanyNameRec =&OrderProducts%5B1%5D.ReceiverModel.OrderReceiver.AddressLineRec =测试+ AMA%C3%A7l%C4%B1D%C4%B1R。+ L&C3%BCtfen + dikkate +爱尔美%C4%B1n的%C4%B1z&OrderProducts%5B1%5D.ProductCode = se213&OrderProducts%5B1%5D.TempOrderProductGuid =%24%7Btokentoken%7D&totalProducts = 1&as_fid = efWZ0i4RGLmC2nBWk%2FA1

3 个解决方案

#1

I would recommend using XPath Extractor instead as regular expressions are pretty dependent on layout, attributes order, spaces, etc. and can be a real headache to develop and test for non-experienced used. Especially multi-line ones.

我建议使用XPath Extractor,因为正则表达式非常依赖于布局,属性顺序,空格等,并且对于没有经验的用户来说,开发和测试可能是一个非常令人头痛的问题。特别是多线的。

XPath expression for extracting value from as_fid input will look like:

用于从as_fid输入中提取值的XPath表达式如下所示:

//input[@id='OrderProducts_1__TempOrderProductGuid']/@value

Some clues:

1. If you're using JMeter 2.11 you'll be able to test your XPath expressions right in View Results Tree Listener

如果您正在使用JMeter 2.11,您将能够在View Results Tree Listener中测试您的XPath表达式

2. You may need to check "Use Tidy" box in XPath Extractor if your HTML isn't XHTML compliant

如果您的HTML不符合XHTML,则可能需要在XPath Extractor中选中“使用整洁”框

3. Check XPath Tutorial for language reference.

检查XPath教程以获取语言参考。

#2

Try this simpler regex for your second case:

在第二种情况下尝试使用这个更简单的正则表达式:

<input.+?value="(.+?)"\s*/>

Demo

http://regex101.com/r/nI8nZ9

#3

You can update the regex as the followings to get the valid DynamicTempOrderProductGuid

您可以将regex更新为以下内容以获取有效的DynamicTempOrderProductGuid

Reference Name: DynamicTempOrderProductGuid 
Regular Expression: name="(.+)"\stype="hidden"value="(.+)"
Template: $2$