两种排课方式：
固定每周的固定时间上课（例：共上20节，每周六、周日早上8点-10点上课。假如今天周六凌晨1点，那么排课也需要从今天开始）总共上几个周，每周上课时间比较个性化（例：共上三周，第一周周一周二早上8点-10点上课；第二周周三周四下午8点-10点上课；第三周周日中午11点-12点上课。）
第一种排课比较好实现，简要代码如下：
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/**
* 生成日期列表
*
* @param int $startDate 开始日期 时间戳格式
* @param array $timeList 课时计划列表
[
{
"start_at": "09:09", //开课时间
"end_at": "10:09", //结束时间
"week_at": 1 //周几
},
{
"start_at": "12:09", //开课时间
"end_at": "13:09", //结束时间
"week_at": 1 //周几
},
{
"start_at": "09:09",
"end_at": "10:09",
"week_at": 5
}
]
* @param int $amount 课时计划数量
* @param int $skipHoliday 跳过节假日
*
* @return array
*/
public function generateDateList($startDate, $timeList, $amount, $skipHoliday = 0)
{
// 计算开始日期是周几
$startDateWeek = intval(date('N', $startDate));
//规范化课时数据 week_at 做key的三维数组
foreach ($timeList as $item) {
$weekAt = $item['week_at'];
array_splice($item, 0, 0, $weekAt);
$key = array_shift($item);
$weeksTime[$key][] = $item;
$item = null;
}
unset($timeList);
if (empty($weeksTime)) {
$this->addError('课时计划数据为空');
return false;
}
//设置跳过假期,获取开始日期之后的节假日
if ($skipHoliday) {
$holiday = new Holiday();
$holidayData = $holiday->getHolidayList($startDate);
$holiday = null;
unset($holiday);
}
$nowTime = time();
$list = array();
for ($weekStartTime = $startDate, $count = 0; $count < $amount; $weekStartTime += 86400 * 7) {
//$currentWeek :周几
foreach ($weeksTime as $currentWeek => $weekTime) {
foreach ($weekTime as $time) {
//算出对应的日期时间戳
$currentDateTime = $weekStartTime + (($startDateWeek <= $currentWeek ? ($currentWeek - $startDateWeek) : (7 - $startDateWeek + $currentWeek)) * 86400);
//对应的日期 = 开始时间 + ((开始时间对应周 <= 数据对应的周几 ？ (数据对应的周几 - 开始时间对应周) ：（7 - 开始时间对应周 + 数据对应的周几）) * 86400)
//假期跳过排课
if ($skipHoliday && !empty($holidayData)) {
$startUnix = $currentDateTime + $time['start_at'] * 3600; //开始时间
$endUnix = $currentDateTime + $time['end_at'] * 3600; //结束时间
$skip = false;
//选择跳过节假日，且节假日与当前课程时间有重叠跳过
foreach ($holidayData as $item) {
if (($item['start_at'] < $endUnix && $item['end_at'] > $startUnix) || ($item['start_at'] === $startUnix && $item['end_at'] === $endUnix)) {
$skip = true;
continue;
}
}
if ($skip) {
continue;
}
}
$currentDate = date('Y/m/d', $currentDateTime);
$startAt = strtotime($currentDate . $time['start_at'] . ':00');
$endAt = strtotime($currentDate . $time['end_at'] . ':00');
if($startAt < $nowTime || $endAt < $nowTime){
$this->addError('上课时间不能小于当前时间');
return false;
}
$list[] = [
'date_at' => $currentDateTime, //日期
'week_at' => $currentWeek, //周几
'start_at' => $startAt,
'end_at' => $endAt
];
$count++;
if ($count >= $amount) {
break 3;
}
}
}
}
$weeksTime = null;
unset($weeksTime);
return $list;
}
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（例子，只用来展示数据结构）假如总共5节课时，从6-25日开始排课，每周一、周六上课：
（例子，只用来展示数据结构）排课结果为：
第二种排课方式稍微麻烦一点，简要代码如下：
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/**
* 生成日期列表
*
* @param int $startDate 开始日期 时间戳格式
* @param array $taskList 任务列表
[
{
"start_at": "09:09", //开始上课时间
"end_at": "10:09", //结束时间
"week_at": 1, //周几
"week_number": 1 //第几周
},
{
"start_at": "09:09",
"end_at": "10:09",
"week_at": 2,
"week_number": 1
},
{
"start_at": "09:09",
"end_at": "10:09",
"week_at": 1,
"week_number": 3
}
]
*
* @return array
*/
public function generateDateList($startDate, $taskList)
{
// 计算开始日期是周几
$startDateWeek = intval(date('N', $startDate));
$list = [];
$nowTime = time();
$weekSign = $week = 0;
foreach($taskList as $key => $task){
if($task['week_number'] > $weekSign && $task['week_number'] != $week){
$weekSign = $task['week_number'] - $week;
}
//计算每条数据对应的日期 $key == 0：确定第一周第一节课是在本周还是下一周
if($key == 0 || $task['week_number'] == $week){
if($task['week'] >= $startDateWeek){
$task['date_at'] = $startDate +
(($weekSign - 1) * 7 + ($task['week'] - $startDateWeek)) * 86400;
}else{
$task['date_at'] = $startDate +
(($weekSign) * 7 - ($startDateWeek - $task['week'])) * 86400;
}
}else{
if($task['week'] > $startDateWeek){
$task['date_at'] = $startDate +
(($weekSign) * 7 + ($task['week'] - $startDateWeek)) * 86400;
}else{
$task['date_at'] = $startDate +
(($weekSign) * 7 - ($startDateWeek - $task['week'])) * 86400;
}
}
$startDateWeek = intval(date('N', $task['date_at']));
$week = $task['week_number'];
$startDate = $task['date_at'];
$dateAt = date('Y/m/d', $task['date_at']);
$startAt = strtotime($dateAt . '00:00:00');
if($task['start_at']){
$startAt = strtotime($dateAt . $task['start_at'] . ':00');
}
$endAt = strtotime($dateAt . '23:59:59');
if($task['end_at']){
$endAt = strtotime($dateAt . $task['end_at'] . ':00');
}
if($startAt < $nowTime || $endAt < $nowTime){
$this->addError('上课时间不能小于当前时间');
return false;
}
$task['start_at'] = $startAt;
$task['end_at'] = $endAt;
//生成课时数据
$list[] = [
'date_at' => $task['date_at'],
'week_at' => $task['week'],
'start_at' => $startAt,
'end_at' => $endAt
];
}
return $list;
}
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（例子，只用来展示数据结构）排课数据：
（例子，只用来展示数据结构） 排课结果：
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原文链接：https://blog.csdn.net/qq_32737755/article/details/118225067