如何列出两个日期之间的所有月份

I'm trying to list all months between two dates.

我想列出两个日期之间的所有月份。

For example; start date is: 2010-12-02 and last date is: 2012-05-06

例如;开课日期是：2010-12-02，最后日期是：2012-05-06

I want to list something like this:

我想列出这样的东西：

This is what I have tried and it is not working at all:

这是我尝试过的，它根本不起作用：

    $year_min = 2010;
    $year_max = 2012;
    $month_min = 12;
    $month_max = 5;
    for($y=$year_min; $y<=$year_max; $y++)
    {
        for($m=$month_min; $m<=$month_max; $m++)
        {
            $period[] = $y.$m;
        }
    }

4 个解决方案

#1

147

PHP 5.3

PHP 5.3

$start    = new DateTime('2010-12-02');
$start->modify('first day of this month');
$end      = new DateTime('2012-05-06');
$end->modify('first day of next month');
$interval = DateInterval::createFromDateString('1 month');
$period   = new DatePeriod($start, $interval, $end);

foreach ($period as $dt) {
    echo $dt->format("Y-m") . "<br>\n";
}

See it in action

看到它在行动

PHP 5.4 or newer

PHP 5.4或更高版本

$start    = (new DateTime('2010-12-02'))->modify('first day of this month');
$end      = (new DateTime('2012-05-06'))->modify('first day of next month');
$interval = DateInterval::createFromDateString('1 month');
$period   = new DatePeriod($start, $interval, $end);

foreach ($period as $dt) {
    echo $dt->format("Y-m") . "<br>\n";
}

The part where we modify the start and end dates to the first of the month is important. If we didn't, and the current day higher then the last day in February (i.e. 28 in non-leap years, 29 in leap years) this would skip February.

我们将开始和结束日期修改为月初的部分非常重要。如果我们没有，并且当前的日子高于2月的最后一天（即非闰年28天，闰年29天），这将超过2月份。

#2

You must make a difference between two months of the same year and two months of different years.

你必须在同一个月的两个月和不同年份的两个月之间做出改变。

$year_min = substr($row['contractStart'], 0, 4);
$year_max = substr($row['contractEnd'], 0, 4);
$month_min = substr($row['contractStart'], 5, 2);
$month_min = substr($row['contractEnd'], 5, 2);
$period = array();
try {
  if ($year_min > $year_max)
    throw new Exception();
  else if ($year_min == $year_max)
    if ($month_min > $month_max)
      throw new Exception();
    for ($month = $month_min; $month <= $month_max; $month++) {
      $period[] = $month . '-' . $year;
    }
  else {
    for ($month = $month_min; $month <= 12; $month++) {
      $period[] = $month . '-' . $year_min;
    }
    for ($year = $year_min + 1; $year < $year_max; $year++) {
      for ($month = $month_min; $month <= $month_max; $month++) {
        $period[] = $month . '-' . $year;
      }
    }
    for ($month = 1; $month <= $month_max; $month++) {
      $period[] = $month . '-' . $year_max;
    }
  }
  implode("<br />\r\n", $period);
}
catch (Exception $e) {
  echo 'Start date occures after end date.'
}

That's for the hard way. Now there is a quick and easy way that is already given as an answer which I recommand you to choose.

这是艰难的方式。现在有一种快速简便的方法已作为答案给出，我建议您选择。

#3

    function getMonthsInRange($startDate, $endDate) {
$months = array();
while (strtotime($startDate) <= strtotime($endDate)) {
    $months[] = array('year' => date('Y', strtotime($startDate)), 'month' => date('m', strtotime($startDate)), );
    $startDate = date('d M Y', strtotime($startDate.
        '+ 1 month'));
}

return $months;
}

#4

This was my solution since DateTime is not available in my server environment.

这是我的解决方案，因为我的服务器环境中没有DateTime。

$a = "2007-01-01";
$b = "2008-02-15";

$i = date("Ym", strtotime($a));
while($i <= date("Ym", strtotime($b))){
    echo $i."\n";
    if(substr($i, 4, 2) == "12")
        $i = (date("Y", strtotime($i."01")) + 1)."01";
    else
        $i++;
}

Try it out: http://3v4l.org/BZOmb

试一试：http：//3v4l.org/BZOmb

#1

147