I have a script for a confirm pop up window.When I call this in our aspx.cs page it returns different values.My script is
我有一个确认弹出窗口的脚本。当我在aspx.cs页面中调用它时,它返回不同的值。我的脚本是
<script type="text/javascript">
function Confirm() {
var confirm_value = document.createElement("INPUT");
confirm_value.type = "hidden";
confirm_value.name = "confirm_value";
if (confirm("Do you want to remove this employee from this group?")) {
confirm_value.value = "1";
} else {
confirm_value.value = "2";
}
document.forms[0].appendChild(confirm_value);
}
Button
<asp:Button ID="btnAdd" OnClientClick = "Confirm()" runat="server" ValidationGroup="1" onclick="btnAdd_Click" />
Button click function
按钮单击功能
protected void btnAdd_Click(object sender, EventArgs e)
{
string confirmValue = Request.Form["confirm_value"];
if (confirmValue == "1")
{
//Do something
}
else
{
//Do something
}
}
First time I clicked cancel then my confirmvalue=="1"
and next time again I selected ok then my confirmvalue=="1,2"
in place of 2. How it returns error value.
我第一次点击取消然后我的确认值==“1”然后我再次选择确定然后我的confirmvalue ==“1,2”代替2.它如何返回错误值。
2 个解决方案
#1
4
You're creating multiple inputs named "confirm_value", one each time you're clicking the button. What you need to do is reuse the same input:
您正在创建名为“confirm_value”的多个输入,每次单击按钮时都会输入一个。您需要做的是重用相同的输入:
function Confirm() {
var confirm_value = document.querySelector('[name="confirm_value"]');
if (!confirm_value) {
confirm_value = document.createElement("INPUT");
confirm_value.type = "hidden";
confirm_value.name = "confirm_value";
document.forms[0].appendChild(confirm_value);
}
if (confirm("Do you want to remove this employee from this group?")) {
confirm_value.value = "1";
} else {
confirm_value.value = "2";
}
}
#2
1
function Confirm() {
var Result=confirm("Do you want to remove this employee from this group?");
var confirm_value = document.querySelector('[name="confirm_value"]');
if (Result) {
return true;
} else {
return false;
}
}
#1
4
You're creating multiple inputs named "confirm_value", one each time you're clicking the button. What you need to do is reuse the same input:
您正在创建名为“confirm_value”的多个输入,每次单击按钮时都会输入一个。您需要做的是重用相同的输入:
function Confirm() {
var confirm_value = document.querySelector('[name="confirm_value"]');
if (!confirm_value) {
confirm_value = document.createElement("INPUT");
confirm_value.type = "hidden";
confirm_value.name = "confirm_value";
document.forms[0].appendChild(confirm_value);
}
if (confirm("Do you want to remove this employee from this group?")) {
confirm_value.value = "1";
} else {
confirm_value.value = "2";
}
}
#2
1
function Confirm() {
var Result=confirm("Do you want to remove this employee from this group?");
var confirm_value = document.querySelector('[name="confirm_value"]');
if (Result) {
return true;
} else {
return false;
}
}