打电话时,按一下按钮

时间:2021-11-23 08:53:15

I'm trying to make a call when I press a button in android

当我按下android上的一个按钮时,我正在试着打电话

((Button)findViewById(R.id.button1)).setOnClickListener(new OnClickListener() {
  @Override
  public void onClick(View v) {
    String phno="10digits";

    Intent i=new Intent(Intent.ACTION_DIAL,Uri.parse(phno));
    startActivity(i);
  }
});

But when I run and click on the button it gives me the error

但是当我运行并点击按钮时它会给我错误

ERROR/AndroidRuntime(1021): android.content.ActivityNotFoundException: No Activity found to handle Intent { act=android.intent.action.CALL dat=9392438004 }

How can I resolve this problem?

我如何解决这个问题?

13 个解决方案

#1


124  

Have you given the permission in the manifest file

你在舱单文件中得到许可了吗

 <uses-permission android:name="android.permission.CALL_PHONE"></uses-permission>   

and inside your activity

和在你的活动

  Intent callIntent = new Intent(Intent.ACTION_CALL);
    callIntent.setData(Uri.parse("tel:123456789"));
    startActivity(callIntent);

Let me know if you find any issue.

如果有什么问题,请告诉我。

#2


12  

change your String to String phno="tel:10digits"; and try again.

将字符串改为String phno="tel:10位";并再次尝试。

#3


11  

There are two intents to call/start calling: ACTION_CALL and ACTION_DIAL.

调用/开始调用有两个意图:ACTION_CALL和ACTION_DIAL。

ACTION_DIAL will only open the dialer with the number filled in, but allows the user to actually call or reject the call. ACTION_CALL will immediately call the number and requires an extra permission.

ACTION_DIAL只会用填充的数字打开拨号器,但允许用户实际调用或拒绝调用。ACTION_CALL将立即调用该号码并需要额外的权限。

So make sure you have the permission

所以一定要得到许可

uses-permission android:name="android.permission.CALL_PHONE"

in your AndroidManifest.xml

在你AndroidManifest.xml

<manifest
    xmlns:android="http://schemas.android.com/apk/res/android"
    package="com.dbm.pkg"
    android:versionCode="1"
    android:versionName="1.0">

    <!-- NOTE! Your uses-permission must be outside the "application" tag
               but within the "manifest" tag. -->

    <uses-permission android:name="android.permission.CALL_PHONE" />

    <application
        android:icon="@drawable/icon"
        android:label="@string/app_name">

        <!-- Insert your other stuff here -->

    </application>

    <uses-sdk android:minSdkVersion="9" />
</manifest> 

#4


9  

None of the above worked so with a bit of tinkering here's code that did for me

上面的这些都没有起作用,所以只要稍加修改,这里的代码就可以为我所用

        Intent i = new Intent(Intent.ACTION_DIAL);
        String p = "tel:" + getString(R.string.phone_number);
        i.setData(Uri.parse(p));
        startActivity(i);

#5


5  

I was having a hell of a time with this as well. I didn't realize that beyond the extra permission you need to append "tel:" onto the string that has the number in it. This is what mine looks like after getting it functional. Hope this helps.

我在这方面也过得很愉快。我没有意识到,除了额外的权限之外,你还需要在字符串中添加“tel:”。这就是我的功能。希望这个有帮助。

@Override
public void onClick(View v) {
  Intent intent = new Intent(Intent.ACTION_DIAL);
  String temp = "tel:" + phone;
  intent.setData(Uri.parse(temp));

  startActivity(intent);
}

#6


4  

add "tel:" along with your number to be dialed in your intent and then start your activity.

添加“电话:”和你的电话号码,然后开始你的活动。

Intent myIntent = new Intent(Intent.ACTION_CALL);
 String phNum = "tel:" + "1234567890";
 myIntent.setData(Uri.parse(phNum));
  startActivity( myIntent ) ;

#7


4  

To have the code within one line, try this:

要将代码放在一行中,请尝试以下方法:

startActivity(new Intent(Intent.ACTION_CALL, Uri.parse("tel:123456789")));

along with the proper manifest permission:

连同适当的舱单许可:

<uses-permission android:name="android.permission.CALL_PHONE"></uses-permission>

Hope this helps!

希望这可以帮助!

#8


2  

For those using AppCompact...Try this

对于那些使用AppCompact…试试这个

import android.support.v7.app.AppCompatActivity;
import android.os.Bundle;
import android.content.Intent;
import android.util.Log;
import android.view.View;
import android.widget.Button;
import android.widget.EditText;
import android.widget.Toast;
import android.net.Uri;

public class MainActivity extends AppCompatActivity {



    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);
        Button startBtn = (Button) findViewById(R.id.db);
        startBtn.setOnClickListener(new View.OnClickListener() {
            public void onClick(View view) {
                makeCall();
            }
        });

    }

    protected void makeCall() {
        EditText num = (EditText)findViewById(R.id.Dail);
        String phone = num.getText().toString();
        String d = "tel:" + phone ;
        Log.i("Make call", "");
        Intent phoneIntent = new Intent(Intent.ACTION_CALL);
        phoneIntent.setData(Uri.parse(d));
        try {
            startActivity(phoneIntent);
            finish();
            Log.i("Finished making a call", "");
        } catch (android.content.ActivityNotFoundException ex) {
            Toast.makeText(this, "Call faild, please try again later.", Toast.LENGTH_SHORT).show();
        }
    }

}

Then add this to your manifest,,,

然后把它添加到你的舱单中,

 <uses-permission android:name="android.permission.CALL_PHONE" />

#9


2  

check permissions before (for android 6 and above):

检查权限前(android 6及以上):

if (ActivityCompat.checkSelfPermission(context, Manifest.permission.CALL_PHONE) ==
                            PackageManager.PERMISSION_GRANTED) 
   {

     context.startActivity(new Intent(Intent.ACTION_CALL, Uri.parse("tel:09130000000")));
   }

#10


1  

Also good to check is telephony supported on device

同样值得检查的是设备上支持的电话

private boolean isTelephonyEnabled(){
TelephonyManager tm = (TelephonyManager)getSystemService(TELEPHONY_SERVICE);
return tm != null && tm.getSimState()==TelephonyManager.SIM_STATE_READY
}

#11


1  

I hope, this short code is useful for You,
   ## Java Code ##
 startActivity(new Intent(Intent.ACTION_DIAL,Uri.parse("tel:"+txtPhn.getText().toString())));



----------------------------------------------------------------------


Please check Manifest File,(for Uses permission)
## Manifest.xml ##
<manifest
    xmlns:android="http://schemas.android.com/apk/res/android"
    package="com.dbm.pkg"
    android:versionCode="1"
    android:versionName="1.0">

    <!-- NOTE! Your uses-permission must be outside the "application" tag
               but within the "manifest" tag. -->
## uses-permission for Making Call ##
    <uses-permission android:name="android.permission.CALL_PHONE" />

    <application
        android:icon="@drawable/icon"
        android:label="@string/app_name">

        <!-- Insert your other stuff here -->

    </application>

    <uses-sdk android:minSdkVersion="9" />
</manifest> 

#12


0  

I've just solved the problem on an Android 4.0.2 device (GN) and the only version working for this device/version was similar to the first 5-starred with CALL_PHONE permission and the answer:

我刚刚在Android 4.0.2设备(GN)上解决了这个问题,这个设备/版本的唯一版本与前一个5星的CALL_PHONE权限相似,答案是:

Intent callIntent = new Intent(Intent.ACTION_CALL);
callIntent.setData(Uri.parse("tel:123456789"));
startActivity(callIntent);

With any other solution i got the ActivityNotFoundException on this device/version. How about the older versions? Would someone give feedback?

有了其他的解决方案,我在这个设备/版本上得到了ActivityNotFoundException。旧版本呢?有人会给反馈吗?

#13


0  

With permission:

许可:

Intent callIntent = new Intent(Intent.ACTION_CALL);
callIntent.setData(Uri.parse("tel:9875432100"));
if (ActivityCompat.checkSelfPermission(yourActivity.this,android.Manifest.permission.CALL_PHONE) != PackageManager.PERMISSION_GRANTED) {
                if (ActivityCompat.shouldShowRequestPermissionRationale(yourActivity.this,
                        android.Manifest.permission.CALL_PHONE)) {
                } else {
                    ActivityCompat.requestPermissions(yourActivity.this,
                            new String[]{android.Manifest.permission.CALL_PHONE},
                            MY_PERMISSIONS_REQUEST_CALL_PHONE);
                }
            }
startActivity(callIntent);

#1


124  

Have you given the permission in the manifest file

你在舱单文件中得到许可了吗

 <uses-permission android:name="android.permission.CALL_PHONE"></uses-permission>   

and inside your activity

和在你的活动

  Intent callIntent = new Intent(Intent.ACTION_CALL);
    callIntent.setData(Uri.parse("tel:123456789"));
    startActivity(callIntent);

Let me know if you find any issue.

如果有什么问题,请告诉我。

#2


12  

change your String to String phno="tel:10digits"; and try again.

将字符串改为String phno="tel:10位";并再次尝试。

#3


11  

There are two intents to call/start calling: ACTION_CALL and ACTION_DIAL.

调用/开始调用有两个意图:ACTION_CALL和ACTION_DIAL。

ACTION_DIAL will only open the dialer with the number filled in, but allows the user to actually call or reject the call. ACTION_CALL will immediately call the number and requires an extra permission.

ACTION_DIAL只会用填充的数字打开拨号器,但允许用户实际调用或拒绝调用。ACTION_CALL将立即调用该号码并需要额外的权限。

So make sure you have the permission

所以一定要得到许可

uses-permission android:name="android.permission.CALL_PHONE"

in your AndroidManifest.xml

在你AndroidManifest.xml

<manifest
    xmlns:android="http://schemas.android.com/apk/res/android"
    package="com.dbm.pkg"
    android:versionCode="1"
    android:versionName="1.0">

    <!-- NOTE! Your uses-permission must be outside the "application" tag
               but within the "manifest" tag. -->

    <uses-permission android:name="android.permission.CALL_PHONE" />

    <application
        android:icon="@drawable/icon"
        android:label="@string/app_name">

        <!-- Insert your other stuff here -->

    </application>

    <uses-sdk android:minSdkVersion="9" />
</manifest> 

#4


9  

None of the above worked so with a bit of tinkering here's code that did for me

上面的这些都没有起作用,所以只要稍加修改,这里的代码就可以为我所用

        Intent i = new Intent(Intent.ACTION_DIAL);
        String p = "tel:" + getString(R.string.phone_number);
        i.setData(Uri.parse(p));
        startActivity(i);

#5


5  

I was having a hell of a time with this as well. I didn't realize that beyond the extra permission you need to append "tel:" onto the string that has the number in it. This is what mine looks like after getting it functional. Hope this helps.

我在这方面也过得很愉快。我没有意识到,除了额外的权限之外,你还需要在字符串中添加“tel:”。这就是我的功能。希望这个有帮助。

@Override
public void onClick(View v) {
  Intent intent = new Intent(Intent.ACTION_DIAL);
  String temp = "tel:" + phone;
  intent.setData(Uri.parse(temp));

  startActivity(intent);
}

#6


4  

add "tel:" along with your number to be dialed in your intent and then start your activity.

添加“电话:”和你的电话号码,然后开始你的活动。

Intent myIntent = new Intent(Intent.ACTION_CALL);
 String phNum = "tel:" + "1234567890";
 myIntent.setData(Uri.parse(phNum));
  startActivity( myIntent ) ;

#7


4  

To have the code within one line, try this:

要将代码放在一行中,请尝试以下方法:

startActivity(new Intent(Intent.ACTION_CALL, Uri.parse("tel:123456789")));

along with the proper manifest permission:

连同适当的舱单许可:

<uses-permission android:name="android.permission.CALL_PHONE"></uses-permission>

Hope this helps!

希望这可以帮助!

#8


2  

For those using AppCompact...Try this

对于那些使用AppCompact…试试这个

import android.support.v7.app.AppCompatActivity;
import android.os.Bundle;
import android.content.Intent;
import android.util.Log;
import android.view.View;
import android.widget.Button;
import android.widget.EditText;
import android.widget.Toast;
import android.net.Uri;

public class MainActivity extends AppCompatActivity {



    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);
        Button startBtn = (Button) findViewById(R.id.db);
        startBtn.setOnClickListener(new View.OnClickListener() {
            public void onClick(View view) {
                makeCall();
            }
        });

    }

    protected void makeCall() {
        EditText num = (EditText)findViewById(R.id.Dail);
        String phone = num.getText().toString();
        String d = "tel:" + phone ;
        Log.i("Make call", "");
        Intent phoneIntent = new Intent(Intent.ACTION_CALL);
        phoneIntent.setData(Uri.parse(d));
        try {
            startActivity(phoneIntent);
            finish();
            Log.i("Finished making a call", "");
        } catch (android.content.ActivityNotFoundException ex) {
            Toast.makeText(this, "Call faild, please try again later.", Toast.LENGTH_SHORT).show();
        }
    }

}

Then add this to your manifest,,,

然后把它添加到你的舱单中,

 <uses-permission android:name="android.permission.CALL_PHONE" />

#9


2  

check permissions before (for android 6 and above):

检查权限前(android 6及以上):

if (ActivityCompat.checkSelfPermission(context, Manifest.permission.CALL_PHONE) ==
                            PackageManager.PERMISSION_GRANTED) 
   {

     context.startActivity(new Intent(Intent.ACTION_CALL, Uri.parse("tel:09130000000")));
   }

#10


1  

Also good to check is telephony supported on device

同样值得检查的是设备上支持的电话

private boolean isTelephonyEnabled(){
TelephonyManager tm = (TelephonyManager)getSystemService(TELEPHONY_SERVICE);
return tm != null && tm.getSimState()==TelephonyManager.SIM_STATE_READY
}

#11


1  

I hope, this short code is useful for You,
   ## Java Code ##
 startActivity(new Intent(Intent.ACTION_DIAL,Uri.parse("tel:"+txtPhn.getText().toString())));



----------------------------------------------------------------------


Please check Manifest File,(for Uses permission)
## Manifest.xml ##
<manifest
    xmlns:android="http://schemas.android.com/apk/res/android"
    package="com.dbm.pkg"
    android:versionCode="1"
    android:versionName="1.0">

    <!-- NOTE! Your uses-permission must be outside the "application" tag
               but within the "manifest" tag. -->
## uses-permission for Making Call ##
    <uses-permission android:name="android.permission.CALL_PHONE" />

    <application
        android:icon="@drawable/icon"
        android:label="@string/app_name">

        <!-- Insert your other stuff here -->

    </application>

    <uses-sdk android:minSdkVersion="9" />
</manifest> 

#12


0  

I've just solved the problem on an Android 4.0.2 device (GN) and the only version working for this device/version was similar to the first 5-starred with CALL_PHONE permission and the answer:

我刚刚在Android 4.0.2设备(GN)上解决了这个问题,这个设备/版本的唯一版本与前一个5星的CALL_PHONE权限相似,答案是:

Intent callIntent = new Intent(Intent.ACTION_CALL);
callIntent.setData(Uri.parse("tel:123456789"));
startActivity(callIntent);

With any other solution i got the ActivityNotFoundException on this device/version. How about the older versions? Would someone give feedback?

有了其他的解决方案,我在这个设备/版本上得到了ActivityNotFoundException。旧版本呢?有人会给反馈吗?

#13


0  

With permission:

许可:

Intent callIntent = new Intent(Intent.ACTION_CALL);
callIntent.setData(Uri.parse("tel:9875432100"));
if (ActivityCompat.checkSelfPermission(yourActivity.this,android.Manifest.permission.CALL_PHONE) != PackageManager.PERMISSION_GRANTED) {
                if (ActivityCompat.shouldShowRequestPermissionRationale(yourActivity.this,
                        android.Manifest.permission.CALL_PHONE)) {
                } else {
                    ActivityCompat.requestPermissions(yourActivity.this,
                            new String[]{android.Manifest.permission.CALL_PHONE},
                            MY_PERMISSIONS_REQUEST_CALL_PHONE);
                }
            }
startActivity(callIntent);