I've got a model (Listings) that has and belongs to a few different models, I'd like to find all of this model where it's related model (Openhouses) have a condition. The 'has and belongs to' are setup in the model files. Listings hasmany Openhouses and Openhouses belong to Listings. (And listings has many and blongs to a few other models where I want the data.)
我有一个模型(列表),它拥有并属于一些不同的模型,我想找到所有这个模型,它的相关模型(Openhouse)有一个条件。 “拥有并属于”是在模型文件中设置的。清单中的开放式房屋和开放式房屋属于清单。 (对于我想要数据的其他一些模型,列表有很多和很多。)
I've been trying.
我一直在努力。
$this->Listing->find('all',
array('conditions' =>
array('Openhouse.date >' => $openhouse_start->format('Y-m-d H:i:s'),
'Openhouse.date <' => $openhouse_end->format('Y-m-d H:i:s'))
));
but to no avail.
但无济于事。
Error: 1054: Unknown column 'Openhouse.date' in 'where clause
I know I can search on the Openhouse model and get related Listings but then the data is returned in a different format and I need to turn recursion way up to get data from my other models. (And I end up with duplicate openhouse data!). I can post some more code examples if needed.
我知道我可以在Openhouse模型上搜索并获得相关的列表但是然后以不同的格式返回数据,我需要将递归方式向上移动以从我的其他模型获取数据。 (最后我得到了重复的openhouse数据!)。如果需要,我可以发布更多代码示例。
My question is basically do I need to just query the openhouse model and live with it or is my syntax for putting conditions on related models incorrect?
我的问题基本上是我需要查询openhouse模型并使用它,还是我的相关模型的条件不正确?
4 个解决方案
#1
Try this:
$this->List->find('all', array(
'contain' => array(
'Openhouse.conditions' => array(
'Openhouse.date >' => $openhouse_start->format('Y-m-d H:i:s'),
'Openhouse.date <' => $openhouse_end->format('Y-m-d H:i:s'))
)
)
)
#2
If you have a lot of linked models, settings recursive to 2 might bring more data than you might want.
如果您有许多链接模型,递归到2的设置可能会带来比您想要的更多的数据。
If that is true, there is an alternative to what mavarro said, you can also try using the Containable behaviour:
如果这是真的,有一种替代mavarro所说的,你也可以尝试使用Containable行为:
$this->Listing->find
(
'all',
array
(
'conditions' => array
(
'Openhouse.date >' => $openhouse_start->format('Y-m-d H:i:s'),
'Openhouse.date <' => $openhouse_end->format('Y-m-d H:i:s')
),
'contain' => array('Openhouse')
)
);
#3
Try adding a $this->Listing->recursive = 2;
before the call to find all. That should link up the tables before the call giving you access to the Openhouse model from the Listing model.
尝试添加$ this-> Listing-> recursive = 2;在通话之前找到所有。这应该在调用之前链接表,使您可以从Listing模型访问Openhouse模型。
#4
$this->List->find('all', array(
'contain' => array(
'conditions' => array(
'Openhouse.date >' => $openhouse_start->format('Y-m-d H:i:s'),
'Openhouse.date <' => $openhouse_end->format('Y-m-d H:i:s')
),
'order' => array('Openhouse.date DESC')
)
)
)
#1
Try this:
$this->List->find('all', array(
'contain' => array(
'Openhouse.conditions' => array(
'Openhouse.date >' => $openhouse_start->format('Y-m-d H:i:s'),
'Openhouse.date <' => $openhouse_end->format('Y-m-d H:i:s'))
)
)
)
#2
If you have a lot of linked models, settings recursive to 2 might bring more data than you might want.
如果您有许多链接模型,递归到2的设置可能会带来比您想要的更多的数据。
If that is true, there is an alternative to what mavarro said, you can also try using the Containable behaviour:
如果这是真的,有一种替代mavarro所说的,你也可以尝试使用Containable行为:
$this->Listing->find
(
'all',
array
(
'conditions' => array
(
'Openhouse.date >' => $openhouse_start->format('Y-m-d H:i:s'),
'Openhouse.date <' => $openhouse_end->format('Y-m-d H:i:s')
),
'contain' => array('Openhouse')
)
);
#3
Try adding a $this->Listing->recursive = 2;
before the call to find all. That should link up the tables before the call giving you access to the Openhouse model from the Listing model.
尝试添加$ this-> Listing-> recursive = 2;在通话之前找到所有。这应该在调用之前链接表,使您可以从Listing模型访问Openhouse模型。
#4
$this->List->find('all', array(
'contain' => array(
'conditions' => array(
'Openhouse.date >' => $openhouse_start->format('Y-m-d H:i:s'),
'Openhouse.date <' => $openhouse_end->format('Y-m-d H:i:s')
),
'order' => array('Openhouse.date DESC')
)
)
)