Example:
I have and array like this:
我有和像这样的数组:
Array( [0] => Apple [2] => Orange [5] => Pear [8] => Pear )
数组([0] => Apple [2] =>橙[5] =>梨[8] =>梨)
there are a function to complete the missing indexes: 1,3,4,6,7????
有一个功能来完成缺失的索引:1,3,4,6,7 ????
4 个解决方案
#1
This should be faster for larger arrays. For smaller arrays any method will do.
对于较大的阵列,这应该更快。对于较小的阵列,任何方法都可以。
$existingKeys = array_keys($array);
//you can use any value instead of null
$newKeys = array_fill_keys(range(min($existingKeys), max($existingKeys)), null);
$array += $newKeys;
//optional, probably not needed
ksort($array);
#2
you could try a for() from the lowest index to the highest and complete if it's empty
您可以尝试从最低索引到最高索引的for(),如果它是空的则完成
for($i = 0 ;$i <= 8 ; $i++)
{
//if it's not set
if(!isset($array[$i]))
{
//set to empty
$array[$i] = "";
}
}
Additionally you could count first the number of elements on the array and wrap it in a function
此外,您可以首先计算阵列上的元素数量并将其包装在函数中
function completeIndexes($array)
{
$total = count($array);
for($i = 0 ;$i < $total ; $i++)
{
//if it's not set
if(!isset($array[$i]))
{
//set to empty
$array[$i] = "";
}
}
return $array;
}
#3
for($i=0;i<count($array);++$i){
$array[$i] = isset($array[$i])? $array[$i] : '';
}
It just fills the missing keys with an empty string, though. Not sure if this suits you.
但它只是用空字符串填充缺少的键。不确定这是否适合你。
Edit
Just noticed Perr0_hunter wrote pretty much the same thing before I did :P
刚刚注意到Perr0_hunter在我做之前写了几乎相同的东西:P
#4
If what you're trying to do is reorder the array so you get
如果你要做的是重新排序数组,那么你得到
Array( [0] => Apple [1] => Orange [2] => Pear [3] => Pear )
Just create a new Array and copy the values into it. It will allocate new indexes sequentially
只需创建一个新数组并将值复制到其中。它将按顺序分配新索引
i.e.
$new_array = array();
for( $value in $old_array )
$new_array[] = $value;
#1
This should be faster for larger arrays. For smaller arrays any method will do.
对于较大的阵列,这应该更快。对于较小的阵列,任何方法都可以。
$existingKeys = array_keys($array);
//you can use any value instead of null
$newKeys = array_fill_keys(range(min($existingKeys), max($existingKeys)), null);
$array += $newKeys;
//optional, probably not needed
ksort($array);
#2
you could try a for() from the lowest index to the highest and complete if it's empty
您可以尝试从最低索引到最高索引的for(),如果它是空的则完成
for($i = 0 ;$i <= 8 ; $i++)
{
//if it's not set
if(!isset($array[$i]))
{
//set to empty
$array[$i] = "";
}
}
Additionally you could count first the number of elements on the array and wrap it in a function
此外,您可以首先计算阵列上的元素数量并将其包装在函数中
function completeIndexes($array)
{
$total = count($array);
for($i = 0 ;$i < $total ; $i++)
{
//if it's not set
if(!isset($array[$i]))
{
//set to empty
$array[$i] = "";
}
}
return $array;
}
#3
for($i=0;i<count($array);++$i){
$array[$i] = isset($array[$i])? $array[$i] : '';
}
It just fills the missing keys with an empty string, though. Not sure if this suits you.
但它只是用空字符串填充缺少的键。不确定这是否适合你。
Edit
Just noticed Perr0_hunter wrote pretty much the same thing before I did :P
刚刚注意到Perr0_hunter在我做之前写了几乎相同的东西:P
#4
If what you're trying to do is reorder the array so you get
如果你要做的是重新排序数组,那么你得到
Array( [0] => Apple [1] => Orange [2] => Pear [3] => Pear )
Just create a new Array and copy the values into it. It will allocate new indexes sequentially
只需创建一个新数组并将值复制到其中。它将按顺序分配新索引
i.e.
$new_array = array();
for( $value in $old_array )
$new_array[] = $value;