I did once counter based on the form. Everything was fine until I have to make changes on the site.
我根据表格做了一次反击。一切都很好,直到我必须在网站上进行更改。
Old code:
<?php
if( isset($_POST['b1']) ) {
$count += 1;
$_SESSION['count'] = $count;
}
(...)
?>
<form action="start.php" method="post">
<button id="b1" class="btn" name="b1"> B1 </button>
<button id="b2" class="btn" name="b2"> B2 </button>
</form>
The form makes problems, so I'm looking for another solution. I was told that I tried Ajax , but it works only $_GET for me (I need post)
表格会产生问题,所以我正在寻找另一种解决方案。我被告知我尝试过Ajax,但它对我来说只有$ _GET(我需要发帖)
What am I doing wrong?
我究竟做错了什么?
<script>
$(document).ready(function(){
$("#b1").click(function(){
$.post("start.php", { name: "b1" });
location.reload();
});
});
</script>
1 个解决方案
#1
0
what you check for is b1 but actually you pass name with b1 as value
你检查的是b1,但实际上你传递的名字是b1作为值
then you need to change your php code to this
那么你需要将你的PHP代码更改为此
<?php
if( isset($_POST['name']) && $_POST['name'] == 'b1' ) {
$count += 1;
$_SESSION['count'] = $count;
}
(...)
?>
UPDATE
if( isset($_POST['name']) && $_POST['name'] == 'b1' ) {
$_SESSION['count'] += 1;
}
#1
0
what you check for is b1 but actually you pass name with b1 as value
你检查的是b1,但实际上你传递的名字是b1作为值
then you need to change your php code to this
那么你需要将你的PHP代码更改为此
<?php
if( isset($_POST['name']) && $_POST['name'] == 'b1' ) {
$count += 1;
$_SESSION['count'] = $count;
}
(...)
?>
UPDATE
if( isset($_POST['name']) && $_POST['name'] == 'b1' ) {
$_SESSION['count'] += 1;
}