如何在单行打印数字

Silly doubt, how can i print numbers in sequence in C programming according to its variable value. my Code

愚蠢的怀疑,我如何根据其变量值在C编程中按顺序打印数字。我的代码

#include <stdio.h>
void main()
{  
   int i,j,result;
   for (i=1;i<=4;i++)
   {
     for (j=i;j<=i;j++)
     {
       printf("%d\n%d",i,j+1);
     }
 }
}

getting output as

获得输出

1
22
33
44

Expecting answer is:

期待的答案是:

1
22
333
4444

3 个解决方案

#1

void main()
{  
   int i,j,result;
   for (i=1;i<=4;i++)
   {
     for (j=1;j<=i;j++)
     {
       printf("%d",i);
     }
     printf("\n");
   }
}

#2

It could help you. Note that in C array indexing starts at 0, not 1.

它可以帮助你。请注意,在C数组中,索引从0开始,而不是1。

void main()
{  
    int i,j;
    for (i = 0; i < 4; ++i)
    {
        for (j = 0; j < i; ++j)
        {
            printf("%d", i);
        }
        printf("\n");
    }
}

#3

#include <stdio.h>
void main()
{  
   int i,j,result;
   for (i=1;i<=4;i++)
   {
     for (j=i;j<=i;j++)
     {
       printf("%d",i);
     }
     printf("\n");
   }
}