var Items = {
FormVariables: function()
{
if (this.array === 'undefined')
{
this.array = [];
}
return this.array;
}
};
This was my attempt at it and I get an error of it being undefined. Can I even have variables within Items scope like I am attempting. If so, what does the syntax look like?
这是我的尝试,我得到一个错误,它是未定义的。我是否可以像我正在尝试的那样在Items范围内拥有变量。如果是这样,语法是什么样的?
I am only asking if this can be done using the var variableName = {}
syntax.
我只是问这是否可以使用var variableName = {}语法来完成。
EDIT:
Accessing it
var formVars = new Array();
formVars.push('[');
for (var item in gd["FormVariables"])
{
formVars.push('"' + item + '":"' + gd["FormVariables"][item] + '"');
}
formVars.push(']');
The real goal here is to take all these items and convert it to a JSON array of key/value pairs
这里的真正目标是获取所有这些项并将其转换为键/值对的JSON数组
1 个解决方案
#1
1
Yes, you can use []
. []
is a shortcut for new Array
, just like {}
is for new Object
.
是的,你可以使用[]。 []是新数组的快捷方式,就像{}是新对象一样。
this.array = [];
By the way, there are no 'compiler errors' since JavaScript is not a compiled language but an interpreted one.
顺便说一下,没有“编译器错误”,因为JavaScript不是一种编译语言,而是一种解释型语言。
Also, your checking does not make much sense. You'd probably want:
此外,您的检查没有多大意义。你可能想要:
if (typeof this.array === 'undefined')
since typeof
returns a string. Checking for the string 'undefined'
is not the same as checking for 'real' undefined
. For the string, it must have been set explicitly to those characters, which is almost never the case.
因为typeof返回一个字符串。检查字符串'undefined'与检查'real'undefined不同。对于字符串,它必须已明确设置为这些字符,这几乎不是这种情况。
#1
1
Yes, you can use []
. []
is a shortcut for new Array
, just like {}
is for new Object
.
是的,你可以使用[]。 []是新数组的快捷方式,就像{}是新对象一样。
this.array = [];
By the way, there are no 'compiler errors' since JavaScript is not a compiled language but an interpreted one.
顺便说一下,没有“编译器错误”,因为JavaScript不是一种编译语言,而是一种解释型语言。
Also, your checking does not make much sense. You'd probably want:
此外,您的检查没有多大意义。你可能想要:
if (typeof this.array === 'undefined')
since typeof
returns a string. Checking for the string 'undefined'
is not the same as checking for 'real' undefined
. For the string, it must have been set explicitly to those characters, which is almost never the case.
因为typeof返回一个字符串。检查字符串'undefined'与检查'real'undefined不同。对于字符串,它必须已明确设置为这些字符,这几乎不是这种情况。