I need to find the index of more than one minimum values that occur in an array. I am pretty known with but it gives me the index of very first minimum value in a array. For example.
我需要找到數組中出現的多個最小值的索引。我很熟悉，但它給了我一個數組中第一個最小值的索引。例如。
a = ([1,2,3,4,5,1,6,1])
print (a)
This gives me 0, instead I am expecting, 0,5,7.
這給了我0，而不是我期待的，0,5,7。
Thanks!
謝謝！
3 个解决方案
#1
21
This should do the trick:
這應該是訣竅：
a = ([1,2,3,4,5,1,6,1])
print (a == ())
argmin doesn't return a list like you expect it to in this case.
在這種情況下，argmin不會像您期望的那樣返回列表。
#2
3
Maybe
也許
mymin = (a)
min_positions = [i for i, x in enumerate(a) if x == mymin]
It will give [0,5,7].
它會給[0,5,7]。
#3
1
I think this would be the easiest way, although it doesn't use any fancy numpy function
我認為這將是最簡單的方法，雖然它不使用任何花哨的numpy功能
a = ([1,2,3,4,5,1,6,1])
min_val = ()
print "min_val = {0}".format(min_val)
# Find all of them
min_idxs = [idx for idx, val in enumerate(a) if val == min_val]
print "min_idxs = {0}".format(min_idxs)