本文实例讲述了C语言实现查看进程是否存在的方法。分享给大家供大家参考,具体如下:
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#include<unistd.h>
#include<sys/types.h>
#include<sys/wait.h>
#include<stdio.h>
#include<stdlib.h>
#include<fcntl.h>
#include<limits.h>
#define BUFSZ 150
void err_quit( char *msg)
{
perror (msg);
exit (EXIT_FAILURE);
}
int main( int argc, char *argv[])
{
FILE * fp;
int count;
char buf[BUFSZ];
char command[150];
sprintf (command, "ps -ef | grep **** | grep -v grep | wc -l" );
if ((fp = popen(command, "r" )) == NULL)
err_quit( "popen" );
if ( ( fgets (buf,BUFSZ,fp))!= NULL )
{
count = atoi (buf);
if (count == 0)
printf ( "not found\n" );
else
printf ( "process :tdv1 total is %d\n" ,count);
}
pclose(fp);
exit (EXIT_SUCCESS);
}
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希望本文所述对大家C语言程序设计有所帮助。