从参考资料中读取XML文件

I have a XML file that I need to parse in the Android SDK.

我有一个XML文件需要在Android SDK中解析。

How can I read the XML file path from resources?

如何从参考资料中读取XML文件路径?

The XML contains:

XML包含:

<Book>
<Chapter>
<NO>   1   </NO>
<Text>  My Lord </Text>
</Chapter> 

<Chapter>
<NO>   1   </NO>
<Text>  My Lord </Text>
</Chapter>
</Book>

3 个解决方案

#1

Put it under your_project_root\res\xml\ folder. Then you can open it with:

把它放在你的_project_root\res xml\文件夹下。然后你可以用:

Resources res = activity.getResources();
XmlResourceParser xrp = res.getXml(R.xml.your_resId);

There is an example on how to use XmlResourceParser here:

这里有一个关于如何使用XmlResourceParser的示例:

http://android-er.blogspot.com/2010/04/read-xml-resources-in-android-using.html

#2

If you have an XML file in the raw folder in your resources then you can read it with the following code:

如果您的资源中的原始文件夹中有一个XML文件，那么您可以使用以下代码来读取它:

Context context = getApplicationContext();
InputStream istream = context.getResources().openRawResource(R.raw.test);

I hope this is useful to you.

我希望这对你有用。

#3

Before parsing xml create one folder inside your resources and put xml file inside that. And try this code.

在解析xml之前，在资源中创建一个文件夹，并将xml文件放在其中。这段代码。

try {
            XmlPullParser xpp=getResources().getXml(R.xml.words);

            while (xpp.getEventType()!=XmlPullParser.END_DOCUMENT) {
                if (xpp.getEventType()==XmlPullParser.START_TAG) {
                    if (xpp.getName().equals("word")) {
                        items.add(xpp.getAttributeValue(0));
                    }
                }

                xpp.next();
            }
        }
        catch (Throwable t) {
            Toast
                .makeText(this, "Request failed: "+t.toString(), Toast.LENGTH_LONG)
                .show();
        }

#1