Java : List中 根据map的某个key去重

  话不多说，看代码和效果

 

     /**
     * 根据map中的某个key 去除List中重复的map
     * @author  shijing
     * @param list
     * @param mapKey
     * @return
     */
    public static List<Map<String, Object>> removeRepeatMapByKey(List<Map<String, Object>> 
           list, String mapKey){
        if ((list)) return null;

        //把list中的数据转换成msp,去掉同一id值多余数据，保留查找到第一个id值对应的数据
        List<Map<String, Object>> listMap = new ArrayList<>();
        Map<String, Map> msp = new HashMap<>();
        for(int i = ()-1 ; i>=0; i--){
            Map map = (i);
            String id = (String)(mapKey);
            (mapKey);
            (id, map);
        }
        //把msp再转换成list,就会得到根据某一字段去掉重复的数据的List<Map>
        Set<String> mspKey = ();
        for(String key: mspKey){
            Map newMap = (key);
            (mapKey, key);
            (newMap);
        }
        return listMap;
    }

测试：

public static void main(String[] args) {
        Map<String, Map> msp = new HashMap<String, Map>();
        List<Map<String, Object>> list = new ArrayList<Map<String, Object>>();
        List<Map<String, Object>> listMap = new ArrayList<Map<String,Object>>();
        Map<String, Object> map1 = new HashMap<String, Object>();
        ("id", "1123");
        ("name", "张三");
        Map<String, Object> map2 = new HashMap<String, Object>();
        ("id", "2");
        ("name", "李四");
        Map<String, Object> map3 = new HashMap<String, Object>();
        ("id", "1123");
        ("name", "王五");
        Map<String, Object> map4 = new HashMap<String, Object>();
        ("id", "3");
        ("name", "赵六");
        (map1);
        (map2);
        (map3);
        (map4);
        ("初始数据：" + ());
        ("去重之后：" + removeRepeatMapByKey(list,"id"));
    }

结果：

初始数据：[{name=张三, id=1123}, {name=李四, id=2}, {name=王五, id=1123}, {name=赵六, id=3}]
去重之后：[{name=李四, id=2}, {name=赵六, id=3}, {name=张三, id=1123}]