有表如下:
create table students
(sno int,
sname varchar(10),
age int);
insert into students values(1,'AARON',20);
insert into students values(2,'CHUCK',21);
insert into students values(3,'DOUG',20);
insert into students values(4,'MAGGIE',19);
insert into students values(5,'STEVE',22);
insert into students values(6,'JING',18);
insert into students values(7,'BRIAN',21);
insert into students values(8,'KAY',20);
insert into students values(9,'GILLIAN',20);
insert into students values(10,'CHAD',21);
求年龄最大的学生?
方式一,我的第一反应是使用聚焦函数max,相信很多人和我一样。
select * from students where age=(select max(age) from students);
简单明了,两次全表扫描,成本6
方式二,有没有不使用max的方法来求最大呢?使用自连接加比较。
select * from students
where age not in (select from students a, students b where < );
先做笛卡尔集,求年龄比任一个小的,再排除他们。三次全表扫描,成本12
方式二的改良
select * from students s1
where not exists (select 1 from students s2 where <);
两次全表扫描,成本8
方式三,使用窗口函数
select * from (select students.*,max(age)over() oldest from students)
where age=oldest;
一次全表扫描,成本3
我本人也有些意料之外,没想到窗口函数威力巨大。
总结:
优先使用窗口函数,然后才是聚集函数;能用exists,就别用in;尽量别做笛卡尔集。