废话不多说：
DateFormat df = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
try
{
Date d1 = ("2018-03-26 13:31:40");
Date d2 = ("2018-01-02 11:30:24");
long diff = () - ();//这样得到的差值是毫秒级别
long days = diff / (1000 * 60 * 60 * 24);
long hours = (diff-days*(1000 * 60 * 60 * 24))/(1000* 60 * 60);
long minutes = (diff-days*(1000 * 60 * 60 * 24)-hours*(1000* 60 * 60))/(1000* 60);
(""+days+"天"+hours+"小时"+minutes+"分");
}catch (Exception e)
{
} 