第09章_子查询练习题
#1.查询和Zlotkey相同部门的员工姓名和工资
SELECT last_name,salary
FROM employees
WHERE department_id IN(
SELECT department_id
FROM employees
WHERE last_name='Zlotkey'
)
#2.查询工资比公司平均工资高的员工的员工号,姓名和工资。
SELECT employee_id,last_name,salary
FROM employees
WHERE salary>(
SELECT AVG(salary)
FROM employees
);
#3.选择工资大于所有JOB_ID = 'SA_MAN'的员工的工资的员工的last_name, job_id, salary
SELECT last_name,job_id,salary
FROM employees
WHERE salary> ALL(
SELECT salary
FROM employees
WHERE job_id='SA_MAN'
);
#4.查询和姓名中包含字母u的员工在相同部门的员工的员工号和姓名
SELECT employee_id,last_name
FROM employees
WHERE department_id IN(
SELECT DISTINCT department_id
FROM employees
WHERE last_name LIKE '%u%'
);
#5.查询在部门的location_id为1700的部门工作的员工的员工号
SELECT employee_id
FROM employees
WHERE department_id IN(
SELECT department_id
FROM departments
WHERE location_id=1700
);
#6.查询管理者是King的员工姓名和工资
SELECT last_name,salary,manager_id
FROM employees
WHERE manager_id IN(
SELECT employee_id
FROM employees
WHERE last_name='King'
);
#7.查询工资最低的员工信息: last_name, salary
SELECT last_name,salary
FROM employees
WHERE salary=(
SELECT MIN(salary)
FROM employees
);
#8.查询平均工资最低的部门信息
SELECT *
FROM departments
WHERE department_id=(
SELECT department_id
FROM employees
GROUP BY department_id
HAVING AVG(salary)=(
SELECT MIN(avg_sal)
FROM(
SELECT AVG(salary) avg_sal
FROM employees
GROUP BY department_id
) t_dept_avg_sal
)
);
#方式2:
SELECT *
FROM departments
WHERE department_id=(
SELECT department_id
FROM employees
GROUP BY department_id
HAVING AVG(salary)<= ALL(
SELECT AVG(salary)
FROM employees
GROUP BY department_id
)
);
#方式3:LIMIT
SELECT *
FROM departments
WHERE department_id=(
SELECT department_id
FROM employees
GROUP BY department_id
HAVING AVG(salary)= (
SELECT AVG(salary) avg_sal
FROM employees
GROUP BY department_id
ORDER BY avg_sal ASC
LIMIT 0,1
)
);
#方式4:
SELECT d.*
FROM departments d,(
SELECT department_id,AVG(salary) avg_sal
FROM employees
GROUP BY department_id
ORDER BY avg_sal ASC
LIMIT 0,1) t_dept_avg_sal
WHERE d.`department_id`=t_dept_avg_sal.department_id
#9.查询平均工资最低的部门信息和该部门的平均工资(相关子查询)
#方式1:
SELECT d.*,(SELECT AVG(salary)
FROM employees WHERE department_id=d.`department_id`) avg_sal
FROM departments d
WHERE department_id=(
SELECT department_id
FROM employees
GROUP BY department_id
HAVING AVG(salary)=(
SELECT MIN(avg_sal)
FROM(
SELECT AVG(salary) avg_sal
FROM employees
GROUP BY department_id
) t_dept_avg_sal
)
);
#方式2:
SELECT d.*,(SELECT AVG(salary)
FROM employees WHERE department_id=d.`department_id`) avg_sal
FROM departments d
WHERE department_id=(
SELECT department_id
FROM employees
GROUP BY department_id
HAVING AVG(salary)<= ALL(
SELECT AVG(salary)
FROM employees
GROUP BY department_id
)
);
#方式3:LIMIT
SELECT d.*,(SELECT AVG(salary)
FROM employees WHERE department_id=d.`department_id`) avg_sal
FROM departments d
WHERE department_id=(
SELECT department_id
FROM employees
GROUP BY department_id
HAVING AVG(salary)= (
SELECT AVG(salary) avg_sal
FROM employees
GROUP BY department_id
ORDER BY avg_sal ASC
LIMIT 0,1
)
);
#方式4:
SELECT d.*,(SELECT AVG(salary)
FROM employees WHERE department_id=d.`department_id`) avg_sal
FROM departments d,(
SELECT department_id,AVG(salary) avg_sal
FROM employees
GROUP BY department_id
ORDER BY avg_sal ASC
LIMIT 0,1) t_dept_avg_sal
WHERE d.`department_id`=t_dept_avg_sal.department_id
#10.查询平均工资最高的 job 信息
#方式1:
SELECT *
FROM jobs
WHERE job_id=(
SELECT job_id
FROM employees
GROUP BY job_id
HAVING AVG(salary)=(
SELECT MAX(avg_sal)
FROM(
SELECT AVG(salary) avg_sal
FROM employees
GROUP BY job_id
) t_job_avg_sal
)
);
#方式2:
SELECT *
FROM jobs
WHERE job_id=(
SELECT job_id
FROM employees
GROUP BY job_id
HAVING AVG(salary)>=ALL(
SELECT AVG(salary)
FROM employees
GROUP BY job_id
)
);
#方式3:
SELECT *
FROM jobs
WHERE job_id=(
SELECT job_id
FROM employees
GROUP BY job_id
HAVING AVG(salary)=(
SELECT AVG(salary) avg_sal
FROM employees
GROUP BY job_id
ORDER BY avg_sal DESC
LIMIT 0,1
)
);
#方式4:
SELECT j.*
FROM jobs j,(
SELECT job_id,AVG(salary) avg_sal
FROM employees
GROUP BY job_id
ORDER BY avg_sal DESC
LIMIT 0,1) t_job_avg_sal
WHERE j.job_id=t_job_avg_sal.job_id
#11.查询平均工资高于公司平均工资的部门有哪些?
SELECT department_id
FROM employees
WHERE department_id IS NOT NULL
GROUP BY department_id
HAVING AVG(salary)>(
SELECT AVG(salary)
FROM employees
);
#12.查询出公司中所有 manager 的详细信息
#方式1:自连接
SELECT DISTINCT mgr.employee_id,mgr.last_name,mgr.job_id,mgr.department_id
FROM employees e1 JOIN employees mgr
ON e1.manager_id=mgr.employee_id
#方式2:子查询
SELECT employee_id,last_name,job_id,department_id
FROM employees
WHERE employee_id IN(
SELECT DISTINCT manager_id
FROM employees
);
#方式3:使用exists
SELECT employee_id,last_name,job_id,department_id
FROM employees e1
WHERE EXISTS(
SELECT *
FROM employees e2
WHERE e1.`employee_id`=e2.`manager_id`
);
#13.各个部门中 最高工资中最低的那个部门的 最低工资是多少?
#方式1:
SELECT MIN(salary)
FROM employees
WHERE department_id=(
SELECT department_id
FROM employees
GROUP BY department_id
HAVING MAX(salary)=(
SELECT MIN(max_sal)
FROM(
SELECT MAX(salary) max_sal
FROM employees
GROUP BY department_id
) t_dept_max_sal
)
);
#方式2:
SELECT MIN(salary)
FROM employees
WHERE department_id=(
SELECT department_id
FROM employees
GROUP BY department_id
HAVING MAX(salary)<= ALL(
SELECT MAX(salary)
FROM employees
GROUP BY department_id
)
);
#方式3:
SELECT MIN(salary)
FROM employees
WHERE department_id=(
SELECT department_id
FROM employees
GROUP BY department_id
HAVING MAX(salary)=(
SELECT MAX(salary) max_sal
FROM employees
GROUP BY department_id
ORDER BY max_sal ASC
LIMIT 0,1
)
);
#方式4:
SELECT MIN(salary)
FROM employees e,(
SELECT department_id,MAX(salary) max_sal
FROM employees
GROUP BY department_id
ORDER BY max_sal ASC
LIMIT 0,1
) t_dept_max_sal
WHERE e.department_id=t_dept_max_sal.department_id
#14.查询平均工资最高的部门的 manager 的详细信息
#: last_name, department_id, email, salary
#方式1:
SELECT last_name,department_id,email,salary
FROM employees
WHERE employee_id =ANY(
SELECT DISTINCT manager_id
FROM employees
WHERE department_id=(
SELECT department_id
FROM employees
GROUP BY department_id
HAVING AVG(salary)=(
SELECT MAX(avg_sal)
FROM(
SELECT AVG(salary) avg_sal
FROM employees
GROUP BY department_id
) t_dept_avg_sal
)
)
);
#方式2:
SELECT last_name,department_id,email,salary
FROM employees
WHERE employee_id =ANY(
SELECT DISTINCT manager_id
FROM employees
WHERE department_id=(
SELECT department_id
FROM employees
GROUP BY department_id
HAVING AVG(salary)>=ALL(
SELECT AVG(salary) avg_sal
FROM employees
GROUP BY department_id
ORDER BY avg_sal DESC
)
)
);
#方式3:
SELECT last_name,department_id,email,salary
FROM employees
WHERE employee_id =ANY(
SELECT DISTINCT manager_id
FROM employees
WHERE department_id=(
SELECT department_id
FROM employees
GROUP BY department_id
HAVING AVG(salary)=(
SELECT AVG(salary) avg_sal
FROM employees
GROUP BY department_id
ORDER BY avg_sal DESC
LIMIT 0,1
)
)
);
#方式4:
SELECT last_name,department_id,email,salary
FROM employees
WHERE employee_id IN(
SELECT DISTINCT manager_id
FROM employees e,(
SELECT department_id,AVG(salary) avg_sal
FROM employees
GROUP BY department_id
ORDER BY avg_sal DESC
LIMIT 0,1
) t_dept_avg_sal
WHERE e.`department_id`=t_dept_avg_sal.department_id
);
#15. 查询部门的部门号,其中不包括job_id是"ST_CLERK"的部门号
#方式1:
SELECT department_id
FROM departments
WHERE department_id NOT IN(
SELECT DISTINCT department_id
FROM employees
WHERE job_id='ST_CLERK'
);
#方式2:
SELECT department_id
FROM departments d
WHERE NOT EXISTS(
SELECT *
FROM employees e
WHERE d.`department_id`=e.`department_id`
AND e.`job_id`='ST_CLERK'
);
#16. 选择所有没有管理者的员工的last_name
SELECT last_name
FROM employees emp
WHERE NOT EXISTS(
SELECT *
FROM employees mgr
WHERE emp.`manager_id`=mgr.`employee_id`
)
#17.查询员工号、姓名、雇用时间、工资,其中员工的管理者为 'De Haan'
# 方式1:
SELECT employee_id,last_name,hire_date,salary
FROM employees
WHERE manager_id=(
SELECT employee_id
FROM employees
WHERE last_name='De Haan'
);
#方式2:
SELECT employee_id,last_name,hire_date,salary
FROM employees e1
WHERE EXISTS(
SELECT *
FROM employees e2
WHERE e1.`manager_id`=e2.`employee_id`
AND e2.`last_name`='De Haan'
);
#18.查询各部门中工资比本部门平均工资高的员工的员工号, 姓名和工资(相关子查询)
SELECT last_name,salary,department_id
FROM employees e1
WHERE salary>(
SELECT AVG(salary)
FROM employees e2
WHERE e2.department_id=e1.`department_id`
);
#19.查询每个部门下的部门人数大于 5 的部门名称(相关子查询)
SELECT department_name
FROM departments d
WHERE 5< (
SELECT COUNT(*)
FROM employees e
WHERE e.`department_id`=d.`department_id`
)
#20.查询每个国家下的部门个数大于 2 的国家编号(相关子查询)
SELECT country_id
FROM locations l
WHERE 2<(
SELECT COUNT(*)
FROM departments d
WHERE l.location_id=d.`location_id`
);
SELECT *
FROM locations
SELECT *FROM departments
/*
子查询的编写技巧(或步骤):① 从里往外写 ②从外往里写
如何选择?
①如果子查询相对较简单,从外往里写,若子查询结构复杂,则从里往外写
②如果是相关子查询的话,通常都是从外往里写
*/