In PHP with DOM, I have a DomElement object which represents an <identity/> element.
在PHP中,我有一个DomElement对象,它表示一个
I have one case where I need to change this so its element name is <person/>, but keep the same child elements and attributes.
我有一种情况,我需要更改它的元素名为
What would be the simplest way of changing an element name of a DomElement and keeping its children and attributes?
更改DomElement的元素名称并保留其子元素和属性的最简单方法是什么?
Edit: I have just found a very similar question (though it doesn't have very good answers).
编辑:我刚刚发现了一个非常相似的问题(虽然它没有很好的答案)。
3 个解决方案
#1
12
Could you use importNode()
to copy the childNodes of your <identity>
element to a newly created <person>
element?
可以使用importNode()将
function changeName($node, $name) {
$newnode = $node->ownerDocument->createElement($name);
foreach ($node->childNodes as $child){
$child = $node->ownerDocument->importNode($child, true);
$newnode->appendChild($child, true);
}
foreach ($node->attributes as $attrName => $attrNode) {
$newnode->setAttribute($attrName, $attrNode);
}
$newnode->ownerDocument->replaceChild($newnode, $node);
return $newnode;
}
$domElement = changeName($domElement, 'person');
Perhaps something like that would work, or you could try using cloneChild()
.
也许这样的方法可行,或者您可以尝试使用cloneChild()。
Edit: Actually, I just realized that the original function would lose the placement of the node. As per the question thomasrutter linked to, replaceChild()
should be used.
编辑:实际上,我刚刚意识到原来的函数会丢失节点的位置。根据与thomasrutter关联的问题,应该使用replaceChild()。
#2
7
Thanks to your post, I could quickly solve the same issue for me. However, I had a DOM_NOT_FOUND exception. This is probably a PHP Version issue, since the original post is 5 years old.
由于你的帖子,我可以很快解决同样的问题。但是,我有一个DOM_NOT_FOUND异常。这可能是一个PHP版本的问题,因为最初的帖子已有5年的历史。
According to the PHP Documentation (Feb 2014)
根据PHP文档(2014年2月)
DOM_NOT_FOUND
Raised if oldnode is not a child of this node.
So, I have replaced
所以,我已经取代了
$newnode->ownerDocument->replaceChild($newnode, $node);
with
与
$node->parentNode->replaceChild($newnode, $node);
Here is the complete function (tested):
以下是完整的功能(已测试):
public static function changeTagName($node, $name) {
$childnodes = array();
foreach ($node->childNodes as $child){
$childnodes[] = $child;
}
$newnode = $node->ownerDocument->createElement($name);
foreach ($childnodes as $child){
$child2 = $node->ownerDocument->importNode($child, true);
$newnode->appendChild($child2);
}
foreach ($node->attributes as $attrName => $attrNode) {
$attrName = $attrNode->nodeName;
$attrValue = $attrNode->nodeValue;
$newnode->setAttribute($attrName, $attrValue);
}
$node->parentNode->replaceChild($newnode, $node);
return $newnode;
}
It is also worth mentioning that when you want to use this function, you should traverse the DOM Tree in reversed order as explained in other posts.
值得一提的是,当您想要使用这个函数时,您应该按相反的顺序遍历DOM树。
UPDATE: After months of using and updating to PHP Version 5.5.15 on windows, I had an error saying $attr could not be converted to a string. So I updated third for-each loop above.
更新:在windows上使用和更新PHP 5.5.15版本几个月后,我有一个错误,说$attr不能转换为字符串。所以我更新了上面的第三个for-each循环。
#3
0
NOTE: I tried Calvin's code and it sort of worked for me but not quite. If the tag I was replacing had nested tags, some child tags would sometimes get lost.
注意:我试过了加尔文的密码,它对我有点效果,但不是很好。如果我替换的标签有嵌套标签,一些子标签有时会丢失。
The reason is that childNodes is a live DOMNodeList of a node's children, and appendChild
moves the nodes around in the DOM, thus affecting the list ordering. If you just do foreach
on a childNodes the loop can skip some children.
原因是子节点是节点子节点的活动DOMNodeList, appendChild移动DOM中的节点,从而影响列表排序。如果你只是对每个孩子都做,循环可以跳过一些孩子。
My solution was to use a while loop. This way you don't have to copy any nodes to an array.
我的解决方案是使用while循环。这样,您不必将任何节点复制到数组中。
I have packaged everything in a convenient function that takes a string and returns a string and should work with utf-8. The following is tested in PHP 5.5.9.
我已经将所有东西打包到一个方便的函数中,该函数接受一个字符串并返回一个字符串,并且应该使用utf-8。下面是在PHP 5.5.9中测试的内容。
function renameTags($html, $oldname, $name) {
$dom = new DOMDocument( '1.0', 'utf-8' );
$fragment = $dom->createDocumentFragment();
if ( $fragment->appendXML( $html ) ) {
$dom->appendChild( $fragment );
$nodesToAlter = $dom->getElementsByTagName( $oldname );
while ($nodesToAlter->length) {
$node = $nodesToAlter->item(0);
$newnode = $node->ownerDocument->createElement($name);
while ($node->hasChildNodes()) {
$child = $node->childNodes->item(0);
$child = $node->ownerDocument->importNode($child, true);
$newnode->appendChild($child);
}
foreach ($node->attributes as $attr) {
$attrName = $attr->nodeName;
$attrValue = $attr->nodeValue;
$newnode->setAttribute($attrName, $attrValue);
}
$newnode->ownerDocument->replaceChild($newnode, $node);
}
return $dom->saveHTML();
} else {
//error
}
}
$html = 'Testing <b foo="bar" baz="foo">nested tags in <i lol="cat"> html strings</i></b> and <b>stuff</b>';
echo renameTags($html, 'b', 'strong');
Prints:
打印:
Testing <strong foo="bar" baz="foo">nested tags in <i lol="cat"> html strings</i></strong> and <strong>stuff</strong>
#1
12
Could you use importNode()
to copy the childNodes of your <identity>
element to a newly created <person>
element?
可以使用importNode()将
function changeName($node, $name) {
$newnode = $node->ownerDocument->createElement($name);
foreach ($node->childNodes as $child){
$child = $node->ownerDocument->importNode($child, true);
$newnode->appendChild($child, true);
}
foreach ($node->attributes as $attrName => $attrNode) {
$newnode->setAttribute($attrName, $attrNode);
}
$newnode->ownerDocument->replaceChild($newnode, $node);
return $newnode;
}
$domElement = changeName($domElement, 'person');
Perhaps something like that would work, or you could try using cloneChild()
.
也许这样的方法可行,或者您可以尝试使用cloneChild()。
Edit: Actually, I just realized that the original function would lose the placement of the node. As per the question thomasrutter linked to, replaceChild()
should be used.
编辑:实际上,我刚刚意识到原来的函数会丢失节点的位置。根据与thomasrutter关联的问题,应该使用replaceChild()。
#2
7
Thanks to your post, I could quickly solve the same issue for me. However, I had a DOM_NOT_FOUND exception. This is probably a PHP Version issue, since the original post is 5 years old.
由于你的帖子,我可以很快解决同样的问题。但是,我有一个DOM_NOT_FOUND异常。这可能是一个PHP版本的问题,因为最初的帖子已有5年的历史。
According to the PHP Documentation (Feb 2014)
根据PHP文档(2014年2月)
DOM_NOT_FOUND
Raised if oldnode is not a child of this node.
So, I have replaced
所以,我已经取代了
$newnode->ownerDocument->replaceChild($newnode, $node);
with
与
$node->parentNode->replaceChild($newnode, $node);
Here is the complete function (tested):
以下是完整的功能(已测试):
public static function changeTagName($node, $name) {
$childnodes = array();
foreach ($node->childNodes as $child){
$childnodes[] = $child;
}
$newnode = $node->ownerDocument->createElement($name);
foreach ($childnodes as $child){
$child2 = $node->ownerDocument->importNode($child, true);
$newnode->appendChild($child2);
}
foreach ($node->attributes as $attrName => $attrNode) {
$attrName = $attrNode->nodeName;
$attrValue = $attrNode->nodeValue;
$newnode->setAttribute($attrName, $attrValue);
}
$node->parentNode->replaceChild($newnode, $node);
return $newnode;
}
It is also worth mentioning that when you want to use this function, you should traverse the DOM Tree in reversed order as explained in other posts.
值得一提的是,当您想要使用这个函数时,您应该按相反的顺序遍历DOM树。
UPDATE: After months of using and updating to PHP Version 5.5.15 on windows, I had an error saying $attr could not be converted to a string. So I updated third for-each loop above.
更新:在windows上使用和更新PHP 5.5.15版本几个月后,我有一个错误,说$attr不能转换为字符串。所以我更新了上面的第三个for-each循环。
#3
0
NOTE: I tried Calvin's code and it sort of worked for me but not quite. If the tag I was replacing had nested tags, some child tags would sometimes get lost.
注意:我试过了加尔文的密码,它对我有点效果,但不是很好。如果我替换的标签有嵌套标签,一些子标签有时会丢失。
The reason is that childNodes is a live DOMNodeList of a node's children, and appendChild
moves the nodes around in the DOM, thus affecting the list ordering. If you just do foreach
on a childNodes the loop can skip some children.
原因是子节点是节点子节点的活动DOMNodeList, appendChild移动DOM中的节点,从而影响列表排序。如果你只是对每个孩子都做,循环可以跳过一些孩子。
My solution was to use a while loop. This way you don't have to copy any nodes to an array.
我的解决方案是使用while循环。这样,您不必将任何节点复制到数组中。
I have packaged everything in a convenient function that takes a string and returns a string and should work with utf-8. The following is tested in PHP 5.5.9.
我已经将所有东西打包到一个方便的函数中,该函数接受一个字符串并返回一个字符串,并且应该使用utf-8。下面是在PHP 5.5.9中测试的内容。
function renameTags($html, $oldname, $name) {
$dom = new DOMDocument( '1.0', 'utf-8' );
$fragment = $dom->createDocumentFragment();
if ( $fragment->appendXML( $html ) ) {
$dom->appendChild( $fragment );
$nodesToAlter = $dom->getElementsByTagName( $oldname );
while ($nodesToAlter->length) {
$node = $nodesToAlter->item(0);
$newnode = $node->ownerDocument->createElement($name);
while ($node->hasChildNodes()) {
$child = $node->childNodes->item(0);
$child = $node->ownerDocument->importNode($child, true);
$newnode->appendChild($child);
}
foreach ($node->attributes as $attr) {
$attrName = $attr->nodeName;
$attrValue = $attr->nodeValue;
$newnode->setAttribute($attrName, $attrValue);
}
$newnode->ownerDocument->replaceChild($newnode, $node);
}
return $dom->saveHTML();
} else {
//error
}
}
$html = 'Testing <b foo="bar" baz="foo">nested tags in <i lol="cat"> html strings</i></b> and <b>stuff</b>';
echo renameTags($html, 'b', 'strong');
Prints:
打印:
Testing <strong foo="bar" baz="foo">nested tags in <i lol="cat"> html strings</i></strong> and <strong>stuff</strong>