Java如何用Stream流将List集合对象中的多个字段拼到一起

• 创建一个对象：Student

import ;
import ;

import ;

@Data
@Accessors(chain = true)
public class Student implements Serializable {
    private static final long serialVersionUID = 1L;

    private String name;    // 名字
    private int age;    // 年龄
    private String sex;  //性别
    private String address;    // 地址
}

• 具体实操，开始拼接：姓名-年龄-性别-地址

public static void main(String[] args) {
   List<Student> studentList = new ArrayList<>();
   Student student1 = new Student();
   ("张三");
   (12);
   ("男");
   ("北京");
   (student1);

   Student student2 = new Student();
   ("李四");
   (15);
   ("男");
   ("上海");
   (student1);

   Student student3 = new Student();
   ("王五");
   (22);
   ("男");
   ("长沙");
   (student1);

   List<String> strList = ().map((Student student) -> {
      (() + "-" + () + "-" + () + "-" + ());
      return student;
   }).map(row -> ()).collect(());

   (strList);
}

• 输出结果：[张三-12-男-北京, 张三-12-男-北京-12-男-北京, 张三-12-男-北京-12-男-北京-12-男-北京]
• 参考文章：你算哪块小饼干咯_JAVA基础,小问题,企业微信-****博客