['CourseAdmin', 'PublishManager', 'ApproveManager', 'ProgramManager'].indexOf(currentRole) > -1 ?
< key="Cancel">Cancel</>
:
null
// indexOf 不存在 返回-1; 权限显示: indexOf 查找 存在的话 返回下标肯定大于0 为true 显示 否则 null
测试:
([‘CourseAdmin’, ‘PublishManager’,‘ApproveManager’,‘ProgramManager’].indexOf(“Guest”) > -1 ?1:2); //2
(['CourseAdmin', 'PublishManager', 'ApproveManager', 'ProgramManager'].indexOf("CourseAdmin")); //0
(['CourseAdmin', 'PublishManager', 'ApproveManager', 'ProgramManager'].indexOf("PublishManager"));//1
在这里插入代码片