Series.str.findall(pat, flags=0, **kwargs)[source]Parameters:
pat : string（Pattern or regular expression）
flags : int, default 0 (no flags)
re module flags, .
Returns:
matches : Series/Index of lists
1、查找单个单词
s = twitter_archive_enhanced_clean['text']
print(('doggo'))
0 []
1 []
2 []
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...
1964 []
1965 []
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1984 [doggo]
1985 []
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1987 []
1988 []
1989 []
1990 []
1991 []
1992 []
1993 []
Name: text, dtype: object