方法一:(比较聪明方法) #某年天数 year_days = 366 if (int(str(year_num))) else 365 #某年某一个月天数 month_days = (int(str(year_num)), int(str(month_num))[1] 方法二:(笨方法) #获取某年一共多少天 def year_days_num(year): #这一年第一天和这一年最后一天 startDay = str(year)+'-01-01' endDay = str(year)+'-12-31' #天数 year_days_mum = ((endDay, "%Y-%m-%d") - (startDay, "%Y-%m-%d")).days +1 print('{}年一共{}天'.format(year,year_days_mum)) return year_days_mum #获取某年某月一共多少天 def month_days_mum(year_days,year_month): #year_month = period对象 '2017-12' num = int(str(year_month).split('-')[1]) if num in (1, 3, 5, 7, 8, 10, 12): month_days = 31 elif num == 2: if year_days==366: # 为闰年 month_days=29 else: month_days = 28 else: month_days = 30 return month_days