《学习记录》“Python”判断今天是今年的第几天

时间:2025-02-09 21:07:14

题目要求:

        编写程序判断今天是今年的第几天?“今天”信息的获取请使用Python标准库time模块的localtime()函数获取。

代码设计:(可运行)

##编写程序判断今天是今年的第几天?“今天”信息的获取请使用Python标准库time模块的localtime()函数获取,具体使用方法如下:
import time

if __name__ == '__main__':
    date = ()  # 获取当前日期时间
    year, month, day = date[:3]
    sumday = 0
    print("{},{},{}".format(year,month,day))
    if  year % 400 == 0 or year % 100 != 0 and year % 4 == 0:
        if 1 < month:
            sumday = sumday + 31
        if 2 < month:
            sumday = sumday + 29
        if 3 < month:
            sumday = sumday + 31
        if 4 < month:
            sumday = sumday + 30
        if 5 < month:
            sumday = sumday + 31
        if 6 < month:
            sumday = sumday + 30
        if 7 < month:
            sumday = sumday + 31
        if 8 < month:
            sumday = sumday + 31
        if 9 < month:
            sumday = sumday + 30
        if 10 < month:
            sumday = sumday + 31
        if 11 < month:
            sumday = sumday + 30
        if 12 < month:
            sumday = sumday + 31
    else:
        if 1 < month:
            sumday = sumday + 31
        if 2 < month:
            sumday = sumday + 28
        if 3 < month:
            sumday = sumday + 31
        if 4 < month:
            sumday = sumday + 30
        if 5 < month:
            sumday = sumday + 31
        if 6 < month:
            sumday = sumday + 30
        if 7 < month:
            sumday = sumday + 31
        if 8 < month:
            sumday = sumday + 31
        if 9 < month:
            sumday = sumday + 30
        if 10 < month:
            sumday = sumday + 31
        if 11 < month:
            sumday = sumday + 30
        if 12 < month:
            sumday = sumday + 31

    sumday = sumday +day

    print("{}".format(sumday))

作者水平有限,刚学习Python,使用了最笨的办法。后续更新其他方法。

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更新其他简单方法,运用数组

import time
if __name__ == '__main__':

    date = ()  # 获取当前日期时间
    year, month, day = date[:3]
    print("{},{},{}".format(year,month,day))
    month_day = [31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31]
    if year % 400 == 0 or year % 100 != 0 and year % 4 == 0:
        month_day[1] = 29
    if month == 1:
        print("{}".format(day))
    else:
        print(sum(month_day[:month-1])+day)