java8中的用法

时间:2024-10-30 13:14:31

根据一个或多个属性对集合中的项目进行分组

数据准备:

public Product(Long id, Integer num, BigDecimal price, String name, String category) {
	 = id;
	 = num;
	 = price;
	 = name;
	 = category;
}

Product prod1 = new Product(1L, 1, new BigDecimal("15.5"), "面包", "零食");
Product prod2 = new Product(2L, 2, new BigDecimal("20"), "饼干", "零食");
Product prod3 = new Product(3L, 3, new BigDecimal("30"), "月饼", "零食");
Product prod4 = new Product(4L, 3, new BigDecimal("10"), "青岛啤酒", "啤酒");
Product prod5 = new Product(5L, 10, new BigDecimal("15"), "百威啤酒", "啤酒");
List<Product> prodList = (prod1, prod2, prod3, prod4, prod5);

分组

  • 按照类目分组:
Map<String, List<Product>> prodMap= ().collect((Product::getCategory));

//{"啤酒":[{"category":"啤酒","id":4,"name":"青岛啤酒","num":3,"price":10},{"category":"啤酒","id":5,"name":"百威啤酒","num":10,"price":15}],"零食":[{"category":"零食","id":1,"name":"面包","num":1,"price":15.5},{"category":"零食","id":2,"name":"饼干","num":2,"price":20},{"category":"零食","id":3,"name":"月饼","num":3,"price":30}]}

  • 按照几个属性拼接分组:
Map<String, List<Product>> prodMap = ().collect((item -> () + "_" + ()));

//{"零食_月饼":[{"category":"零食","id":3,"name":"月饼","num":3,"price":30}],"零食_面包":[{"category":"零食","id":1,"name":"面包","num":1,"price":15.5}],"啤酒_百威啤酒":[{"category":"啤酒","id":5,"name":"百威啤酒","num":10,"price":15}],"啤酒_青岛啤酒":[{"category":"啤酒","id":4,"name":"青岛啤酒","num":3,"price":10}],"零食_饼干":[{"category":"零食","id":2,"name":"饼干","num":2,"price":20}]}

  • 根据不同条件分组
Map<String, List<Product>> prodMap= ().collect((item -> {
	if(() < 3) {
		return "3";
	}else {
		return "other";
	}
}));

//{"other":[{"category":"零食","id":3,"name":"月饼","num":3,"price":30},{"category":"啤酒","id":4,"name":"青岛啤酒","num":3,"price":10},{"category":"啤酒","id":5,"name":"百威啤酒","num":10,"price":15}],"3":[{"category":"零食","id":1,"name":"面包","num":1,"price":15.5},{"category":"零食","id":2,"name":"饼干","num":2,"price":20}]}

多级分组

要实现多级分组,我们可以使用一个由双参数版本的工厂方法创 建的收集器,它除了普通的分类函数之外,还可以接受collector类型的第二个参数。那么要进 行二级分组的话,我们可以把一个内层groupingBy传递给外层groupingBy,并定义一个为流 中项目分类的二级标准。

Map<String, Map<String, List<Product>>> prodMap= ().collect((Product::getCategory, (item -> {
	if(() < 3) {
		return "3";
	}else {
		return "other";
	}
})));

//{"啤酒":{"other":[{"category":"啤酒","id":4,"name":"青岛啤酒","num":3,"price":10},{"category":"啤酒","id":5,"name":"百威啤酒","num":10,"price":15}]},"零食":{"other":[{"category":"零食","id":3,"name":"月饼","num":3,"price":30}],"3":[{"category":"零食","id":1,"name":"面包","num":1,"price":15.5},{"category":"零食","id":2,"name":"饼干","num":2,"price":20}]}}

按子组收集数据

  • 求总数
Map<String, Long> prodMap = ().collect((Product::getCategory, ()));

//{"啤酒":2,"零食":3}
  • 求和
Map<String, Integer> prodMap = ().collect((Product::getCategory, (Product::getNum)));

//{"啤酒":13,"零食":6}
  • 把收集器的结果转换为另一种类型
Map<String, Product> prodMap = ().collect((Product::getCategory, (((Product::getNum)), Optional::get)));

//{"啤酒":{"category":"啤酒","id":5,"name":"百威啤酒","num":10,"price":15},"零食":{"category":"零食","id":3,"name":"月饼","num":3,"price":30}}

  • 联合其他收集器
Map<String, Set<String>> prodMap = ().collect((Product::getCategory, (Product::getName, ())));

//{"啤酒":["青岛啤酒","百威啤酒"],"零食":["面包","饼干","月饼"]}

相关链接:
java8中map新增方法详解
java8中Stream的使用
java8中Collection新增方法详解
java8中Collectors的方法使用实例
java8中常用函数式接口
java8中的方法引用和构造函数引用
java8中的用法
java8中的Optional用法
java8中的日期和时间API