【C语言刷力扣】1768.交替合并字符串

时间:2024-10-27 16:06:02

题目:

解题思路:

        将 word1 和 word2 元素依次添加至 ans 的后面。

时间复杂度: O(n+m) ,  n是word1的长度  m是word2的长度

空间复杂度: O(n+m)

char* mergeAlternately(char* word1, char* word2) {
    int len1 = strlen(word1);
    int len2 = strlen(word2);
    int j = 0;
    char* ans = (char*)malloc(sizeof(char) * (len1 + len2 + 1));
    for (int i = 0; i < len1 || i < len2; i++) {
        if (i < len1) {
            ans[j++] = word1[i];
        }
        if (i < len2) {
            ans[j++] = word2[i];
        }
    }
    ans[j] = '\0';
    return ans;
}