用逗号分隔字符串，但忽略引号内的逗号[duplicate]

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这个问题在这里已有答案：

Split a string by commas but ignore commas within double-quotes using Javascript 9 answers
用逗号分隔字符串但使用Javascript 9答案忽略双引号中的逗号

Example string:

示例字符串：

"Foo","Bar, baz","Lorem","Ipsum"

Here we have 4 values in quotes separated by commas.

这里我们用引号分隔4个引号值。

When I do this:

我这样做的时候：

str.split(',').forEach(…

than that will also split the value "Bar, baz" which I don't want. Is it possible to ignore commas inside quotes with a regular expression?

比那还要分割我不想要的“Bar，baz”这个值。是否可以使用正则表达式忽略引号内的逗号？

1 个解决方案

#1

One way would be using a Positive Lookahead assertion here.

一种方法是在这里使用Positive Lookahead断言。

var str = '"Foo","Bar, baz","Lorem","Ipsum"',
    res = str.split(/,(?=(?:(?:[^"]*"){2})*[^"]*$)/);

console.log(res);  // [ '"Foo"', '"Bar, baz"', '"Lorem"', '"Ipsum"' ]

Regular expression:

正则表达式：

,               ','
(?=             look ahead to see if there is:
(?:             group, but do not capture (0 or more times):
(?:             group, but do not capture (2 times):
 [^"]*          any character except: '"' (0 or more times)
 "              '"'
){2}            end of grouping
)*              end of grouping
 [^"]*          any character except: '"' (0 or more times)
$               before an optional \n, and the end of the string
)               end of look-ahead

Or a Negative Lookahead

或者是负面的前瞻

var str = '"Foo","Bar, baz","Lorem","Ipsum"',
    res = str.split(/,(?![^"]*"(?:(?:[^"]*"){2})*[^"]*$)/);

console.log(res); // [ '"Foo"', '"Bar, baz"', '"Lorem"', '"Ipsum"' ]

#1