Django Rest Framework：如何为基于函数的视图启用swagger文档

I went through Django REST Swagger 2.1.2 documentation. When I tried with class based views, it was working fine.

我浏览了Django REST Swagger 2.1.2文档。当我尝试使用基于类的视图时，它工作正常。

But i did not find any reference on how to enable swagger for function based views as shown below:

但我没有找到任何关于如何为基于函数的视图启用swagger的参考，如下所示：

@api_view(['GET', 'POST'])
def app_info(request): 
    ...
    return response

Most of my views.py is filled with function based views, just like above.

我的大多数views.py都填充了基于函数的视图，就像上面一样。

Any help on how to enable the same will greatly appreciated. Thanks!

如何启用相同的任何帮助将非常感激。谢谢！

I am using Django: 1.8; Django REST Swagger: 2.1.2; DRF: 3.6.2

我正在使用Django：1.8; Django REST Swagger：2.1.2; DRF：3.6.2

2 个解决方案

#1

You should be able to use @renderer_classes decorator:

你应该可以使用@renderer_classes装饰器：

from rest_framework_swagger import renderers
from rest_framework.decorators import api_view, renderer_classes


@api_view(['GET', 'POST'])
@renderer_classes([renderers.OpenAPIRenderer, renderers.SwaggerUIRenderer])
def app_info(request): 
    ...
    return response

Also, it should be worth mentioning, that if you don't want to use this decorator on every view you can specify DEFAULT_RENDERER_CLASSES in settings

此外，值得一提的是，如果您不想在每个视图上使用此装饰器，您可以在设置中指定DEFAULT_RENDERER_CLASSES

EDIT: It seems it's in the docs after all. Check the very bottom of this page: https://django-rest-swagger.readthedocs.io/en/latest/schema/

编辑：毕竟它似乎在文档中。请查看本页底部：https：//django-rest-swagger.readthedocs.io/en/latest/schema/

#2

i am not fammiliar with swagger,but you may try to use the decorator in this way:

我并不熟悉招摇，但您可以尝试以这种方式使用装饰器：

class TestView(View):
    @api_view(['GET', 'POST'])
    def get(self, request):
        ....

or

要么

from django.utils.decorators import method_decorator
class TestView(View):
    @method_decorator(api_view(['GET', 'POST'])
    def get(self, request):
        ....

----------------------------------------------------------------------------

sorry, maybe i have misunderstood your question. according to the document, if you want to enable swagger in class based view. there is example:

对不起，也许我误解了你的问题。根据文档，如果你想在基于类的视图中启用swagger。有例子：

from rest_framework.permissions import AllowAny
from rest_framework.response import Response
from rest_framework.schemas import SchemaGenerator
from rest_framework.views import APIView
from rest_framework_swagger import renderers


class SwaggerSchemaView(APIView):
    permission_classes = [AllowAny]
    renderer_classes = [
        renderers.OpenAPIRenderer,
        renderers.SwaggerUIRenderer
    ]

    def get(self, request):
        generator = SchemaGenerator()
        schema = generator.get_schema(request=request)
        return Response(schema)

restframework will use these two renderer_classes to render Json and UI.

restframework将使用这两个renderer_classes来呈现Json和UI。