本文实例讲述了Java实现打印二叉树所有路径的方法。分享给大家供大家参考,具体如下:
问题:
给一个二叉树,把所有的路径都打印出来。
比如,对于下面这个二叉树,它所有的路径为:
8 -> 3 -> 1
8 -> 2 -> 6 -> 4
8 -> 3 -> 6 -> 7
8 -> 10 -> 14 -> 13
思路:
从根节点开始,把自己的值放在一个数组里,然后把这个数组传给它的子节点,子节点同样把自己的值放在这个数组里,又传给自己的子节点,直到这个节点是叶节点,然后把这个数组打印出来。所以,我们这里要用到递归。
代码:
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/**
Given a binary tree, prints out all of its root-to-leaf
paths, one per line. Uses a recursive helper to do the work.
*/
public void printPaths(Node root, int n) {
String[] path = new String[n];
printPaths(root, path, 0 );
}
/**
Recursive printPaths helper -- given a node, and an array containing
the path from the root node up to but not including this node,
prints out all the root-leaf paths.
*/
private void printPaths(Node node, String[] path, int pathLen) {
if (node == null ) return ;
// append this node to the path array
path[pathLen++] = node.value;
// it's a leaf, so print the path that led to here
if (node.leftChild == null && node.rightChild == null ) {
printArray(path, pathLen);
}
else {
// otherwise try both subtrees
printPaths(node.leftChild, path, pathLen);
printPaths(node.rightChild, path, pathLen);
}
}
/**
Utility that prints strings from an array on one line.
*/
private void printArray(String[] ints, int len) {
for ( int i = 0 ; i < len; i++) {
System.out.print(ints[i] + " " );
}
System.out.println();
}
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备注:这里只能用一个数组+一个数值才能打印出所需要的路径,如果用linkedlist之类的链表结构是不行的。值得分析一下原因,很有意思。
希望本文所述对大家java程序设计有所帮助。
原文链接:http://blog.csdn.net/samjustin1/article/details/52561831