C++实现推箱子小游戏

本文实例为大家分享了C++实现推箱子小游戏的具体代码，供大家参考，具体内容如下

游戏效果

简单易懂的推箱子闯关小游戏。

游戏代码

#include <bits/stdc++.h>
#include <windows.h>
#include <conio.h>
using namespace std;
#define VERSION "2.2"
#define M 55
int n, m, wall[M][M], hole[M][M], box[M][M];
int step, dct, query, cross, rx[233], ry[233];
char str[M][M], title[M], o;
char atlas[M][M][M] = {
 {"...#@.","@..*..","#*##..","..##*#","..X.&.",".@#..."},
 {"########...####","########..*####","########*....##","######.*..*..##"
 ,"@@..##.###.#...","@@.X......*..*.","@@..#.####.####","#####......####"},
 {"####..#...##","##.*..*.#.##","...#.**#....","X*.....#*##.","#.*###**....","##..##.#*..."
 ,"###@@@.#.*#.","###@@@@@#.*.","####@@@@@...","#######.#*.#","#######....#","#######...##"},
 {"..@*.##",".@*@*..","&*@*@X.",".@*@*.#","..@*..#"}
};
int A[M] = {6, 8, 12, 5}, B[M] = {6, 15, 12, 7};
struct pos {
 int x, y;
} player;
struct node {
 pos man;
 int dct;
 vector<pos> box;
 node() {
 box.clear ();
 }
} rec[M * M * M];
void color (int x);
void clean ();
bool check (int x, int y, int cross);
bool forward (int rx, int ry);
bool win ();
void pt ();
void update ();
void playing ();
void in ();
void pass ();
void Init ();
void remain ();
int main() {
 MessageBox (NULL, "欢迎来到推箱子游戏！", "温馨提示", MB_OK);
 Init ();
 while (true) {
 remain ();
 }
 return 0;
}
void color (int x) {
 SetConsoleTextAttribute (GetStdHandle (STD_OUTPUT_HANDLE), x);
}
void clean () {
 system("cls");
 color(7);
}
bool check (int x, int y, int cross) {
 if (!cross) {
  return x < 1 || x > n || y < 1 || y > m || wall[x][y];
 }
 return x < 0 || x > n + 1 || y < 0 || y > m + 1;
}
bool forward (int rx, int ry) {
 int x = player.x + rx, y = player.y + ry, X = x + rx, Y = y + ry;
 if (check (x,y,cross)) {
 return false;
 }
 if(box[x][y]) {
 if (check (X, Y, 0) || box[X][Y]) {
 return false;
 }
 }
 return true;
}
bool win () {
 for (int i = 0; i < rec[step].box.size (); i++) {
 if (!hole[rec[step].box[i].x][rec[step].box[i].y]) {
 return false;
 }
 }
 return true;
}
void pt () {
 memset (box, 0, sizeof (box));
 for (int i = 0; i < rec[step].box.size (); i++) {
  box[rec[step].box[i].x][rec[step].box[i].y] = 1;
 }
 player.x = rec[step].man.x;
 player.y = rec[step].man.y;
 dct = rec[step].dct;
 clean ();
 color (154);
 puts ("按方向键进行移动,按删除键进行撤销");
 puts ("按空格键查询步数。");
 puts ("按0返回,按Esc键退出游戏");
 color (7);
 for (int i = 0; i <= n + 1; i++) {
 printf(" ");
  for (int j = 0; j <= m + 1; j++) {
 if (i == player.x && j == player.y) {
    color (15);
 if (check (i, j, 0)) {
  color (63);
 }
 printf ("♀");
    color (7);
   } else if (i == 0 || i == n + 1 || j == 0 || j == m + 1 || wall[i][j]) {
 color (3);
 printf ("■");
 } else if(box[i][j]) {
 color (14);
    if (hole[i][j]) {
  color (12);
 }
    printf ("▓");
   } else if (hole[i][j]) {
 color (3);
 printf ("※");
 } else {
 printf (" ");
 }
  }
 puts ("");
 }
 color (7);
}
void update () {
 node temp;
 int i, j;
 for (i = 1; i <= n; i++) {
 for (j = 1; j <= m; j++) {
 if (box[i][j]) {
 pos po;
 po.x = i;
 po.y = j;
 temp.box.push_back (po);
 }
 }
 }
 temp.man.x = player.x;
 temp.man.y = player.y;
 temp.dct = dct;
 rec[step] = temp;
}
void playing () {
 dct = 72;
 step = 0;
 update ();
 pt ();
 int winstep = -1;
 while (o = getch ()) {
 int tp = 0;
 if (o == 72 || o == 77 || o == 80 || o == 75) {
 if (forward (rx[o],ry[o])) {
 int x = player.x + rx[o], y = player.y + ry[o];
 if (box[x][y]) {
  box[x][y] = 0;
  box[x + rx[o]][y + ry[o]] = 1;
 }
 player.x = x;
 player.y = y;
 step++;
 } else {
 tp = 1;
 }
 dct = o;
 update ();
 } else if (o == 8) {
 tp = 3;
 step = max (0, step - 1);
 if (step <= winstep) {
 winstep = -1;
 }
 } else if (o == 48) {
 break;
 }
 else if (o == 27) {
 exit (0);
 }
 else if (o == 32) {
 query ^= 1;
 }
 else {
 tp = 2;
 }
 pt ();
 color (154);
 if (query) {
 printf ("当前步数为%d！\n", step);
 }
 if(win () || winstep != -1) {
 if (winstep == -1) {
 winstep = step;
 }
 printf ("恭喜您，您赢了！共用了%d步。\n", winstep);
 MessageBox (NULL, "恭喜您，您赢了！", "温馨提示", MB_OK);
 } else if (tp == 1) {
 color (207);
 puts("对不起，您无法推动这个方块！");
 } else if (tp == 2) {
 color (207);
 } else if (tp == 3) {
 puts ("撤销成功！");
 }
 color (7);
 }
}
void in () {
 memset (wall, 0, sizeof (wall));
 memset (hole, 0, sizeof(hole));
 memset (box, 0, sizeof(box));
 clean ();
 puts ("第一行输入两个整数n和m，表示地图的大小");
 puts ("接下来n行，每行m个元素。");
 puts ("'.'表示空地");
 puts ("'#'表示墙");
 puts ("'*'表示箱子");
 puts ("'@'表示洞");
 puts ("'X'表示人" );
 puts ("'&'表示箱子已在洞上");
 scanf ("%d %d", &n, &m);
 int i,j;
 for (i = 1; i <= n; i++) {
 scanf ("%s", str[i] + 1);
 }
 for (i = 1; i <= n; i++) {
 for (j = 1; j <= m; j++) {
 o = str[i][j];
 if (o == 'X') {
 player.x = i;
 player.y = j;
 }
 if (o == '#') {
 wall[i][j] = 1;
 }
 if (o == '@' || o == '&') {
 hole[i][j] = 1;
 }
 if (o == '*' || o =='&') {
 box[i][j] = 1;
 }
 }
 }
 playing ();
}
void pass () {
 memset (wall, 0, sizeof (wall));
 memset (hole, 0, sizeof (hole));
 memset (box, 0, sizeof (box));
 clean ();
 puts ("1.第一关");
 puts ("2.第二关");
 puts ("3.第三关");
 puts ("4.第四关");
 puts ("\n0.返回");
 puts ("Esc.退出游戏");
 while (o = getch ()) {
 if (o >= '1' && o <= '4') {
 int id = o - 48 - 1;
 n = A[id];
 m = B[id];
 for (int i = 1; i <= n; i++) {
 for (int j = 1; j <= m; j++) {
  char o = atlas[id][i - 1][j - 1];
  if (o == 'X') {
  player.x = i;
  player.y = j;
  }
  if (o == '#') {
  wall[i][j] = 1;
  }
  if (o == '@' || o == '&') {
  hole[i][j] = 1;
  }
  if (o == '*' || o =='&') {
  box[i][j] = 1;
  }
  }
 }
 playing ();
 break;
 } else if (o == 48) {
 break;
 }
 }
}
void Init () {
 system ("mode con cols=40 lines=20");
 SetConsoleTitle ("推箱子");
 rx[72] = -1;
 rx[80] = 1;
 ry[77] = 1;
 ry[75] = -1;
}
void remain () {
 clean ();
 puts ("1.闯关模式");
 puts ("2.输入模式");
 puts ("Esc.退出游戏");
 while (o = getch ()) {
 if (o=='1') {
 pass ();
 break;
 } else if (o == '2') {
 in ();
 break;
 } else if (o == 27) {
 exit (0);
 }
 }
}

以上就是本文的全部内容，希望对大家的学习有所帮助，也希望大家多多支持服务器之家。

原文链接：https://blog.csdn.net/yueyuedog/article/details/112506963