什么是逻辑上结合布尔列表的最“pythonic”方式？

I have a list of booleans I'd like to logically combine using and/or. The expanded operations would be:

我有一个布尔列表我想用逻辑组合使用和/或。扩展的业务将是:

vals = [True, False, True, True, True, False]

# And-ing them together
result = True
for item in vals:
    result = result and item

# Or-ing them together
result = False
for item in vals:
    result = result or item

Are there nifty one-liners for each of the above?

上面的每一个都有漂亮的单行吗?

3 个解决方案

#1

See all(iterable) :

查看全部(可迭代):

Return True if all elements of the iterable are true (or if the iterable is empty).

如果iterable的所有元素都为true(或者iterable为空),则返回True。

And any(iterable) :

任何(可迭代的):

Return True if any element of the iterable is true. If the iterable is empty, return False.

如果iterable的任何元素为true,则返回True。如果iterable为空,则返回False。

#2

The best way to do it is with the any() and all() functions.

最好的方法是使用any()和all()函数。

vals = [True, False, True, True, True]
if any(vals):
   print "any() reckons there's something true in the list."
if all(vals):
   print "all() reckons there's no non-True values in the list."
if any(x % 4 for x in range(100)):
   print "One of the numbers between 0 and 99 is divisible by 4."

#3

Demonstrating NullUserException's answer.

演示NullUserException的答案。

In [120]: a
Out[120]: 
array([[ True,  True,  True,  True],
       [ True,  True,  True,  True],
       [ True,  True,  True,  True],
       [ True,  True,  True,  True],
       [ True,  True,  True,  True]], dtype=bool)

In [121]: a.all()
Out[121]: True

In [122]: b
Out[122]: 
array([[False,  True,  True,  True],
       [ True,  True,  True,  True],
       [ True,  True,  True,  True],
       [ True,  True,  True,  True],
       [ True,  True,  True,  True]], dtype=bool)

In [123]: b.all()
Out[123]: False

In [124]: b.any()
Out[124]: True

#1