本文实例讲述了Python基于递归算法求最小公倍数和最大公约数。分享给大家供大家参考，具体如下：
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# 最小公倍数
def lcm(a, b, c=1):
if a * c % b != 0:
return lcm(a, b, c+1)
else:
return a*c
test_cases = [(4, 8), (35, 42), (5, 7), (20, 10)]
for case in test_cases:
print('lcm of {} & {} is {}'.format(*case, lcm(*case)))
def lcm(a, b):
for i in range(2, min(a,b)+1):
if a % i == 0 and b % i == 0:
return i * lcm(a//i, b//i)
else:
return a*b
test_cases = [(4, 8), (5, 7), (24, 16), (35, 42)]
for case in test_cases:
print('lcm of {} & {} is {}'.format(*case, lcm(*case)))
# 最大公约数
def gcd(a, b):
if a == b:
return a
elif a-b > b:
return gcd(a-b, b)
else:
return gcd(b, a-b)
test_cases = [(35, 14), (88, 66), (5, 4), (20, 10)]
for case in test_cases:
print('GCD of {} & {} is {}'.format(*case, gcd(*case)))
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运行结果：
lcm of 4 & 8 is 8
lcm of 35 & 42 is 210
lcm of 5 & 7 is 35
lcm of 20 & 10 is 20
GCD of 35 & 14 is 7
GCD of 88 & 66 is 22
GCD of 5 & 4 is 1
GCD of 20 & 10 is 10
希望本文所述对大家Python程序设计有所帮助。
原文链接：https://blog.csdn.net/xpresslink/article/details/78875473