采用队列实现,BFS,功能:BFS层次遍历打印、按照节点将BFS序列化成一个字符。
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#include <iostream>
#include <string>
#include <queue>
using namespace std;
struct TreeNode
{
int val;
TreeNode* left;
TreeNode* right;
TreeNode( int val) : val(val), left(nullptr), right(nullptr) {}
};
//迭代打印层次遍历
void BFSTraverse(TreeNode* root)
{
queue<TreeNode*> nodeQueue;
nodeQueue.push(root); //先把第一个先放到列表里面
while (!nodeQueue.empty())
{
int sz = nodeQueue.size(); //这个是为了一层一层的数值进行处理
for ( int i = 0; i < sz; i++)
{
//那就取出那个节点进行处理
TreeNode* node = nodeQueue.front();
cout << node->val << ", " ;
nodeQueue.pop();
if (node->left)
{
nodeQueue.push(node->left);
}
if (node->right)
{
nodeQueue.push(node->right);
}
}
}
}
//按照节点进行序列化成一个字符串
string serialByBFS(TreeNode* root)
{
if (root == nullptr)
return "#!" ;
queue<TreeNode*> nodeQueue;
nodeQueue.push(root);
string res;
while (!nodeQueue.empty())
{
int sz = nodeQueue.size();
for ( int i = 0; i < sz; i++)
{
TreeNode* node = nodeQueue.front();
nodeQueue.pop();
if (node)
{
res = res + std::to_string(node->val) + '!' ;
nodeQueue.push(node->left);
nodeQueue.push(node->right);
}
else
{
res = res + "#!" ;
}
}
}
return res;
}
int main3()
{
TreeNode* head = new TreeNode(5);
head->left = new TreeNode(3);
head->right = new TreeNode(8);
head->left->left = new TreeNode(1);
head->left->right = new TreeNode(2);
head->right->left = new TreeNode(4);
head->right->right = new TreeNode(5);
head->right->left->left = new TreeNode(6);
head->right->right->left = new TreeNode(9);
head->right->right->right = new TreeNode(11);
cout << "traverse1:" ;
BFSTraverse(head);
cout << "\nserial binary:" ;
string res = serialByBFS(head);
cout << res << endl;
return 0;
}
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ps:下面看下C++层次遍历
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/*
* description:层次遍历
* writeby: nick
* date: 2012-10-22 23:56
*/
#include <iostream>
#include <queue>
using namespace std;
struct node
{
int item;
node *l, *r;
node( int n)
{
item=n;
l=0;
r=0;
}
};
typedef node *link;
void traverse(link h, void visit(link))
{
queue<link> q;
q.push(h);
while (!q.empty())
{
h = q.front();
q.pop();
visit(h);
if (h->l != 0) q.push(h->l);
if (h->r !=0) q.push(h->r);
}
}
void visit(link p)
{
cout << p->item << " " ;
}
int main()
{
link root = new node(4);
root->l = new node(5);
root->r = new node(6);
root->l->l = new node(7);
root->l->r = new node(8);
cout << "中文" ;
traverse(root, visit);
return 0;
}
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原文链接:https://www.cnblogs.com/logic03/p/15107619.html