in template:
<script type="text/javascript">
$.ajax({
type:"POST",
url:"{% url DrHub.views.ajxTest %}",
data: {
'start': $('#id_startTime').val(),
'end': $('#id_endTime').val(),
'csrfmiddlewaretoken': '{{ csrf_token }}'
},
success: function(data){
alert(data);
}
});
</script>
.
.
.
<form method='POST' action=".">
{% csrf_token %}
<input type="text id="id_startTime" />
<input type="text id="id_endTime" />
<input type="submit" value="send" />
</form>
in views:
def ajxTest(request):
if request.is_ajax():
if request.method == 'POST':
return HttpResponse(json.dumps({'message' : 'awesome'},ensure_ascii=False), mimetype='application/javascript')
in settings.py:
MIDDLEWARE_CLASSES = (
'django.middleware.common.CommonMiddleware',
'django.contrib.sessions.middleware.SessionMiddleware',
'django.middleware.csrf.CsrfViewMiddleware',
'django.contrib.auth.middleware.AuthenticationMiddleware',
'django.contrib.messages.middleware.MessageMiddleware',
'django.contrib.messages.middleware.MessageMiddleware',
'django.middleware.locale.LocaleMiddleware',
)
when submitting form I have this error:CSRF verification failed. Request aborted.
提交表单时出现此错误:CSRF验证失败。请求中止。
I searched alot but none of suggested solutions worked for me!
我搜索了很多,但没有一个建议的解决方案适合我!
like : Django CSRF check failing with an Ajax POST request
像:Django CSRF检查失败的Ajax POST请求
and : Ajax Post in Django framework?
和:Django框架中的Ajax Post?
I refreenced to a js file with this content:
我用这个内容重新刷新了一个js文件:
$.ajaxSetup({
beforeSend: function(xhr, settings) {
function getCookie(name) {
var cookieValue = null;
if (document.cookie && document.cookie != '') {
var cookies = document.cookie.split(';');
for (var i = 0; i < cookies.length; i++) {
var cookie = jQuery.trim(cookies[i]);
// Does this cookie string begin with the name we want?
if (cookie.substring(0, name.length + 1) == (name + '=')) {
cookieValue = decodeURIComponent(cookie.substring(name.length + 1));
break;
}
}
}
return cookieValue;
}
if (!(/^http:.*/.test(settings.url) || /^https:.*/.test(settings.url))) {
// Only send the token to relative URLs i.e. locally.
xhr.setRequestHeader("X-CSRFToken", getCookie('csrftoken'));
}
}
});
but this didn't work,too!
但这也行不通!
And I saw a solution that say use ajaxSetup instead of ajaxSend to post data,how can I do this?
我看到一个解决方案,说使用ajaxSetup而不是ajaxSend来发布数据,我该怎么做?
6 个解决方案
#1
5
You should pull the csrfmiddlewaretoken from the dom element:
你应该从dom元素中提取csrfmiddlewaretoken:
{'csrfmiddlewaretoken':$( "#csrfmiddlewaretoken" ).val()}
{'csrfmiddlewaretoken':$(“#csrfmiddlewaretoken”)。val()}
The above is exactly what I do in several places and it works.
以上就是我在几个地方做的事情,它的确有效。
Edit just to add some clarity drawing from your material:
编辑只是为了从材料中添加一些清晰度图:
<script type="text/javascript">
$.ajax({
type:"POST",
url:"{% url DrHub.views.ajxTest %}",
data: {
'start': $('#id_startTime').val(),
'end': $('#id_endTime').val(),
'csrfmiddlewaretoken':$( "#csrfmiddlewaretoken" ).val()
},
success: function(data){
alert(data);
}
});
</script>
#2
2
having this a refrence to a js file with this content was my solution:
有这个内容的js文件的参考是我的解决方案:
jQuery(document).ajaxSend(function(event, xhr, settings) {
function getCookie(name) {
var cookieValue = null;
if (document.cookie && document.cookie != '') {
var cookies = document.cookie.split(';');
for (var i = 0; i < cookies.length; i++) {
var cookie = jQuery.trim(cookies[i]);
// Does this cookie string begin with the name we want?
if (cookie.substring(0, name.length + 1) == (name + '=')) {
cookieValue = decodeURIComponent(cookie.substring(name.length + 1));
break;
}
}
}
return cookieValue;
}
function sameOrigin(url) {
// url could be relative or scheme relative or absolute
var host = document.location.host; // host + port
var protocol = document.location.protocol;
var sr_origin = '//' + host;
var origin = protocol + sr_origin;
// Allow absolute or scheme relative URLs to same origin
return (url == origin || url.slice(0, origin.length + 1) == origin + '/') ||
(url == sr_origin || url.slice(0, sr_origin.length + 1) == sr_origin + '/') ||
// or any other URL that isn't scheme relative or absolute i.e relative.
!(/^(\/\/|http:|https:).*/.test(url));
}
function safeMethod(method) {
return (/^(GET|HEAD|OPTIONS|TRACE)$/.test(method));
}
if (!safeMethod(settings.type) && sameOrigin(settings.url)) {
xhr.setRequestHeader("X-CSRFToken", getCookie('csrftoken'));
}
});
#3
2
There's also another shortcut to this. I wouldn't know if the security thing here is of so much value and importance. I ran into this problem but there seems to be a lot of hacks around this that end up trying to submit the csrftoken from an existing cookie. I don't know what would happen if this cookie does not exist or was not set.
还有另一个捷径。我不知道这里的安全问题是否具有如此重要的价值和重要性。我遇到了这个问题,但似乎有很多黑客攻击,最终试图从现有的cookie提交csrftoken。我不知道如果这个cookie不存在或没有设置会发生什么。
My approach was to add a @csrf_exempt
to the view that processes the ajax post. You import the csrf_exempt
from django.views.decorators.csrf
我的方法是将@csrf_exempt添加到处理ajax帖子的视图中。您从django.views.decorators.csrf导入csrf_exempt
Like this:
from django.views.decorators.csrf import csrf_exempt
And than, from the view method:
而且,从视图方法:
@csrf_exempt
def the_method_to_be_called(request):
...
see this link
看到这个链接
#4
0
Please add the csrfmiddlewaretoken as csrfmiddlewaretoken
: {% csrf_token %}
in your js.
请在您的js中将csrfmiddlewaretoken添加为csrfmiddlewaretoken:{%csrf_token%}。
<script type="text/javascript">
$.ajax({
type:"POST",
url:"{% url DrHub.views.ajxTest %}",
data: {
'start': $('#id_startTime').val(),
'end': $('#id_endTime').val(),
'csrfmiddlewaretoken': '{% csrf_token %}'
},
success: function(data){
alert(data);
}
});
</script>
#5
0
in HTML(template)
{% csrf_token %}
in JS
$.ajax({
type: "POST",
url: '/brand-admin/publish_article/',
data: {
'article_id': article_id,
'csrfmiddlewaretoken':$( "input[name='csrfmiddlewaretoken']" ).val()
},
dataType: 'json',
success: function (data) {
console.log(data);
}
});
#6
0
If the {% csrf_token %}
is in your form on your template:
如果您的模板中的表单中包含{%csrf_token%}:
<form id="the-form" autocomplete="off">
{% csrf_token %}
<input type="text" name="q">
<input type="submit" value="Submit">
</form>
you should be able to send it up using:
你应该能够使用以下方式发送它:
$("#the-form").submit(function(e){
e.preventDefault();
$.ajax({
type: "POST",
url: "/post-url",
data: $("#the-form").serialize(),
success: function(data){
console.log(data);
}
});
});
#1
5
You should pull the csrfmiddlewaretoken from the dom element:
你应该从dom元素中提取csrfmiddlewaretoken:
{'csrfmiddlewaretoken':$( "#csrfmiddlewaretoken" ).val()}
{'csrfmiddlewaretoken':$(“#csrfmiddlewaretoken”)。val()}
The above is exactly what I do in several places and it works.
以上就是我在几个地方做的事情,它的确有效。
Edit just to add some clarity drawing from your material:
编辑只是为了从材料中添加一些清晰度图:
<script type="text/javascript">
$.ajax({
type:"POST",
url:"{% url DrHub.views.ajxTest %}",
data: {
'start': $('#id_startTime').val(),
'end': $('#id_endTime').val(),
'csrfmiddlewaretoken':$( "#csrfmiddlewaretoken" ).val()
},
success: function(data){
alert(data);
}
});
</script>
#2
2
having this a refrence to a js file with this content was my solution:
有这个内容的js文件的参考是我的解决方案:
jQuery(document).ajaxSend(function(event, xhr, settings) {
function getCookie(name) {
var cookieValue = null;
if (document.cookie && document.cookie != '') {
var cookies = document.cookie.split(';');
for (var i = 0; i < cookies.length; i++) {
var cookie = jQuery.trim(cookies[i]);
// Does this cookie string begin with the name we want?
if (cookie.substring(0, name.length + 1) == (name + '=')) {
cookieValue = decodeURIComponent(cookie.substring(name.length + 1));
break;
}
}
}
return cookieValue;
}
function sameOrigin(url) {
// url could be relative or scheme relative or absolute
var host = document.location.host; // host + port
var protocol = document.location.protocol;
var sr_origin = '//' + host;
var origin = protocol + sr_origin;
// Allow absolute or scheme relative URLs to same origin
return (url == origin || url.slice(0, origin.length + 1) == origin + '/') ||
(url == sr_origin || url.slice(0, sr_origin.length + 1) == sr_origin + '/') ||
// or any other URL that isn't scheme relative or absolute i.e relative.
!(/^(\/\/|http:|https:).*/.test(url));
}
function safeMethod(method) {
return (/^(GET|HEAD|OPTIONS|TRACE)$/.test(method));
}
if (!safeMethod(settings.type) && sameOrigin(settings.url)) {
xhr.setRequestHeader("X-CSRFToken", getCookie('csrftoken'));
}
});
#3
2
There's also another shortcut to this. I wouldn't know if the security thing here is of so much value and importance. I ran into this problem but there seems to be a lot of hacks around this that end up trying to submit the csrftoken from an existing cookie. I don't know what would happen if this cookie does not exist or was not set.
还有另一个捷径。我不知道这里的安全问题是否具有如此重要的价值和重要性。我遇到了这个问题,但似乎有很多黑客攻击,最终试图从现有的cookie提交csrftoken。我不知道如果这个cookie不存在或没有设置会发生什么。
My approach was to add a @csrf_exempt
to the view that processes the ajax post. You import the csrf_exempt
from django.views.decorators.csrf
我的方法是将@csrf_exempt添加到处理ajax帖子的视图中。您从django.views.decorators.csrf导入csrf_exempt
Like this:
from django.views.decorators.csrf import csrf_exempt
And than, from the view method:
而且,从视图方法:
@csrf_exempt
def the_method_to_be_called(request):
...
see this link
看到这个链接
#4
0
Please add the csrfmiddlewaretoken as csrfmiddlewaretoken
: {% csrf_token %}
in your js.
请在您的js中将csrfmiddlewaretoken添加为csrfmiddlewaretoken:{%csrf_token%}。
<script type="text/javascript">
$.ajax({
type:"POST",
url:"{% url DrHub.views.ajxTest %}",
data: {
'start': $('#id_startTime').val(),
'end': $('#id_endTime').val(),
'csrfmiddlewaretoken': '{% csrf_token %}'
},
success: function(data){
alert(data);
}
});
</script>
#5
0
in HTML(template)
{% csrf_token %}
in JS
$.ajax({
type: "POST",
url: '/brand-admin/publish_article/',
data: {
'article_id': article_id,
'csrfmiddlewaretoken':$( "input[name='csrfmiddlewaretoken']" ).val()
},
dataType: 'json',
success: function (data) {
console.log(data);
}
});
#6
0
If the {% csrf_token %}
is in your form on your template:
如果您的模板中的表单中包含{%csrf_token%}:
<form id="the-form" autocomplete="off">
{% csrf_token %}
<input type="text" name="q">
<input type="submit" value="Submit">
</form>
you should be able to send it up using:
你应该能够使用以下方式发送它:
$("#the-form").submit(function(e){
e.preventDefault();
$.ajax({
type: "POST",
url: "/post-url",
data: $("#the-form").serialize(),
success: function(data){
console.log(data);
}
});
});