话说上过洛谷的都知道，有一道经典例题P1000超级马里奥，这一题，可以说是非常简单非常经典，但是就算如此，还是可以人才辈出，我是个比较循规蹈矩的人（雾），所以我的代码就比较平常，也就是直接输出了所要求的超级马里奥的图片，那道题题目是这样的
超级玛丽是一个非常经典的游戏。请你用字符画的形式输出超级玛丽中的一个场景。
******** ************ ####....#. #..###.....##.... ###.......###### ### ### ........... #...# #...# ##*####### #.#.# #.#.# ####*******###### #.#.# #.#.# ...#***.****.*###.... #...# #...# ....**********##..... ### ### ....**** *****.... #### #### ###### ###### ############################################################## #...#......#.##...#......#.##...#......#.##------------------# ###########################################------------------# #..#....#....##..#....#....##..#....#....##################### ########################################## #----------#一般人都会写个cout+endl来实现输出的操作，但是，网友的力量是强大的，只有想不到没有做不到的，
#.....#......##.....#......##.....#......# #----------# ########################################## #----------# #.#..#....#..##.#..#....#..##.#..#....#..# #----------# ########################################## ############
接下来我介绍几种 ，注意，非原创
比如这位大佬，看之前先来一波膜拜orz，orz；
#include <bits/stdc++.h> using namespace std; int mp[100][100]; int last[100]; int n = 22, m = 62; // 在[x1-x2, y1-y2]绘制ch void draw(int x1, int y1, int x2, int y2, char ch = \'#\'){ for(int i = x1; i <= x2; i++) for(int j = y1; j <= y2; j++) mp[i][j] = ch; } // 在[x1, y1]绘制ch void draw(int x1, int y1, char ch = \'#\'){ draw(x1, y1, x1, y1, ch); } // 以[x, y]为左上角绘制泥土 void drawland(int x, int y){ draw(x, y, x+8, y+13); for(int i = x+1; i < x+8; i+=2) draw(i, y+1, i, y+12, \'.\'); draw(x+1, y+4); draw(x+1, y+11); draw(x+3, y+3); draw(x+3, y+8); draw(x+5, y+6); draw(x+7, y+2); draw(x+7, y+5); draw(x+7, y+10); } // 以[x, y]为左上角绘制小岛 void drawisland(int x, int y){ draw(x, y, x+3, y+19); draw(x+1, y+1, x+2, y+18, \'-\'); draw(x+4, y+4, x+8, y+15); draw(x+4, y+5, x+7, y+14, \'-\'); } // 以[x, y]为左上角绘制金币 void drawcoin(int x, int y){ draw(x, y, x+5, y+4); draw(x+1, y+1, x+4, y+3, \'.\'); draw(x+2, y+2, x+3, y+2); draw(x, y, \' \'); draw(x+5, y, \' \'); draw(x, y+4, \' \'); draw(x+5, y+4, \' \'); } // 以[x, y]为左上角绘制马里奥 void drawman(int x, int y){ draw(x, y+5, x, y+12, \'*\'); x++; draw(x, y+4, x, y+15, \'*\'); x++; draw(x, y+4, x, y+7); draw(x, y+8, x, y+13, \'.\'); draw(x, y+12); x++; draw(x, y+2, x, y+14); draw(x, y+3, x, y+4, \'.\'); draw(x, y+8, x, y+12, \'.\'); draw(x, y+15, x, y+18, \'.\'); x++; draw(x, y+2, x, y+17); draw(x, y+5, x, y+11, \'.\'); x++; draw(x, y+5, x, y+15, \'.\'); x++; draw(x, y+4, x, y+13); draw(x, y+6, \'*\'); x++; draw(x, y+1, x, y+17); draw(x, y+5, x, y+11, \'*\'); x++; draw(x, y, x+2, y+20, \'.\'); draw(x, y+4, x+2, y+16, \'*\'); draw(x, y+3); draw(x, y+14, x+1, y+16); draw(x+1, y+16, \'.\'); draw(x+2, y+8, x+2, y+11, \' \'); draw(x, y+7, \'.\'); draw(x, y+12, \'.\'); draw(x+3, y, x+4, y+19); draw(x+3, y+6, x+4, y+13, \' \'); draw(x+3, y, x+3, y+1, \' \'); draw(x+3, y+18, x+3, y+19, \' \'); } // 打印输出 void printscreen(){ for(int i = 1; i <= n; i++){ last[i] = m; while(mp[i][last[i]] == \' \') last[i]--; } for(int i = 1; i <= n; i++,puts("")) for(int j = 1; j <= last[i]; j++) putchar(mp[i][j]); } int main(){ for(int i = 1; i <= n; i++) for(int j = 1; j <= m; j++) mp[i][j] = \' \'; // 绘制人 drawman(1, 12); // 绘制他脚下的三块泥土 drawland(14, 1); drawland(14, 15); drawland(14, 29); // 绘制金币下面的那个岛屿 drawisland(14, 43); // 绘制两个金币 drawcoin(5, 43); drawcoin(5, 58); // 输出 printscreen(); return 0; }
大致也看完了吧，这个人，不，这位大佬以坐标的方式，一个一个的把字符输出，最后达到了一样的效果，不得不说，这也太强了吧，你也去试试吧（雾）
如果只有这么点我也不会说是人才辈出了，下面这位可以说是暴力出奇迹了（雾）
#include<iostream> #include<cstdio> #include<cstdlib> #include<cmath> #include<cstring> #include<string> #include<algorithm> #include<climits> #include<cfloat> #include<queue> #include<cstddef> using namespace std; char x; int a[10000]={32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,42,42,42,42,42,42,42,42,10,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,42,42,42,42,42,42,42,42,42,42,42,42,10,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,35,35,35,35,46,46,46,46,35,46,10,32,32,32,32,32,32,32,32,32,32,32,32,32,35,46,46,35,35,35,46,46,46,46,46,35,35,46,46,46,46,10,32,32,32,32,32,32,32,32,32,32,32,32,32,35,35,35,46,46,46,46,46,46,46,35,35,35,35,35,35,32,32,32,32,32,32,32,32,32,32,32,32,32,32,35,35,35,32,32,32,32,32,32,32,32,32,32,32,32,35,35,35,10,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,46,46,46,46,46,46,46,46,46,46,46,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,35,46,46,46,35,32,32,32,32,32,32,32,32,32,32,35,46,46,46,35,10,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,35,35,42,35,35,35,35,35,35,35,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,35,46,35,46,35,32,32,32,32,32,32,32,32,32,32,35,46,35,46,35,10,32,32,32,32,32,32,32,32,32,32,32,32,35,35,35,35,42,42,42,42,42,42,42,35,35,35,35,35,35,32,32,32,32,32,32,32,32,32,32,32,32,32,35,46,35,46,35,32,32,32,32,32,32,32,32,32,32,35,46,35,46,35,10,32,32,32,32,32,32,32,32,32,32,32,46,46,46,35,42,42,42,46,42,42,42,42,46,42,35,35,35,46,46,46,46,32,32,32,32,32,32,32,32,32,32,35,46,46,46,35,32,32,32,32,32,32,32,32,32,32,35,46,46,46,35,10,32,32,32,32,32,32,32,32,32,32,32,46,46,46,46,42,42,42,42,42,42,42,42,42,42,35,35,46,46,46,46,46,32,32,32,32,32,32,32,32,32,32,32,35,35,35,32,32,32,32,32,32,32,32,32,32,32,32,35,35,35,10,32,32,32,32,32,32,32,32,32,32,32,46,46,46,46,42,42,42,42,32,32,32,32,42,42,42,42,42,46,46,46,46,10,32,32,32,32,32,32,32,32,32,32,32,32,32,35,35,35,35,32,32,32,32,32,32,32,32,35,35,35,35,10,32,32,32,32,32,32,32,32,32,32,32,35,35,35,35,35,35,32,32,32,32,32,32,32,32,35,35,35,35,35,35,10,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,10,35,46,46,46,35,46,46,46,46,46,46,35,46,35,35,46,46,46,35,46,46,46,46,46,46,35,46,35,35,46,46,46,35,46,46,46,46,46,46,35,46,35,35,45,45,45,45,45,45,45,45,45,45,45,45,45,45,45,45,45,45,35,10,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,45,45,45,45,45,45,45,45,45,45,45,45,45,45,45,45,45,45,35,10,35,46,46,35,46,46,46,46,35,46,46,46,46,35,35,46,46,35,46,46,46,46,35,46,46,46,46,35,35,46,46,35,46,46,46,46,35,46,46,46,46,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,10,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,32,32,32,32,35,45,45,45,45,45,45,45,45,45,45,35,10,35,46,46,46,46,46,35,46,46,46,46,46,46,35,35,46,46,46,46,46,35,46,46,46,46,46,46,35,35,46,46,46,46,46,35,46,46,46,46,46,46,35,32,32,32,32,35,45,45,45,45,45,45,45,45,45,45,35,10,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,32,32,32,32,35,45,45,45,45,45,45,45,45,45,45,35,10,35,46,35,46,46,35,46,46,46,46,35,46,46,35,35,46,35,46,46,35,46,46,46,46,35,46,46,35,35,46,35,46,46,35,46,46,46,46,35,46,46,35,32,32,32,32,35,45,45,45,45,45,45,45,45,45,45,35,10,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,35,32,32,32,32,35,35,35,35,35,35,35,35,35,35,35,35,10}; int main() { for(int i = 0;i <= 1148;i++) { cout<<(char)a[i]; } return 0; }
打表。。。
这也未尝不是一种不错的方法，能存下所有的坐标，也是厉害所在啊%%%！这些还不够达到人才辈出，没错，还有优秀的代码优秀的人！
接下来是优秀的人，但看他的代码没什么出众的地方，但是他的题解可以说是很有文化了，我截取他的代码的其中一段的题解
吾有一術。名之曰「画点」。欲行是術。必先得三數。曰「甲」。曰「乙」。曰「字」。乃行是術曰。 施「画」於「甲」。於「乙」。於「甲」。於「乙」。於「字」。 是謂「画点」之術也。 吾有一術。名之曰「画地」。欲行是術。必先得二數。曰「甲」。曰「乙」。乃行是術曰。 加「甲」以八。名之曰「丙」。加「乙」以十三。名之曰「丁」。 施「画」於「甲」。於「乙」。於「丙」。於「丁」。於「井」。 吾有一列。名之曰「戊」。充「戊」以一。以三。以五。以七。 凡「戊」中之「己」。 加「己」以「甲」。名之曰「庚」。加「乙」以一。名之曰「丙」。加「乙」以十二。名之曰「丁」。 施「画」於「庚」。於「丙」。於「庚」。於「丁」。於「点」。 云云。
#include<stdio.h> int main() { printf( " ********\n" " ************\n" " ####....#.\n" " #..###.....##....\n" " ###.......###### ### ###\n" " ........... #...# #...#\n" " ##*####### #.#.# #.#.#\n" " ####*******###### #.#.# #.#.#\n" " ...#***.****.*###.... #...# #...#\n" " ....**********##..... ### ###\n" " ....**** *****....\n" " #### ####\n" " ###### ######\n" "##############################################################\n" "#...#......#.##...#......#.##...#......#.##------------------#\n" "###########################################------------------#\n" "#..#....#....##..#....#....##..#....#....#####################\n" "########################################## #----------#\n" "#.....#......##.....#......##.....#......# #----------#\n" "########################################## #----------#\n" "#.#..#....#..##.#..#....#..##.#..#....#..# #----------#\n" "########################
################## ############\n" ); return 0; }
看着题解，心里自愧不如，你说编程不比别人好也就算了，语文也被吊打。。。
今天的内容就只有这些了，在最后，请广大博主帮我看看，这个代码是什么意思？（雾）python学的少，没见过世面（大雾）
import zlib,base64;print zlib.decompress(base64.b64decode(\'eJylUkEOwCAIu/sKk95Mxv+fN2AsE0S3xR42sRYqUqtHM5TJfsaBQQyQZ3jTGLp+JcqIjBUMSUMYy1Z6EB1J0hCOrhuywnoeXo4gF5U1I0nxJhc3rKSmH2vDd/Ny+nkMa6I3F7xmallrgvRh0K9L4DzLPLZQ9IY2CdekTKNjwK/qqdwK4J7TeZSa/wxtWKjc3W4VjdKdqt2tsIp2q3Y4AbV3oO4=\')).decode()