I would like to do the equivalent off this (ruby code) in python for a Django project I am working on. I want to make a filmstrip image of X number of images in a folder.
我想在python中为我正在研究的Django项目做相同的(ruby代码)。我想在一个文件夹中制作X个图像的幻灯片图像。
2 个解决方案
#1
1
Here is a function that wraps the contact sheet function S.Lott mentioned.
这是一个包含S.Lott提到的联系表函数的函数。
#!/usr/bin/env python
import os, os.path
from contactsheet import make_contact_sheet
def make_film_strip(fnames,
(photow,photoh),
(marl,mart,marr,marb),
padding):
return make_contact_sheet(fnames,
(1, len(fnames)),
(photow,photoh),
(marl,mart,marr,marb),
padding)
It is assuming the recipe is saved as contactsheet.py
. Usage is:
假设配方保存为contactsheet.py。用法是:
fstrip = filmstrip.make_film_strip(filmstrip.fnames, (120, 120), (0,0,0,0), 0)
fstrip.save('/path/to/file.format')
Tested.
#2
4
Do you mnean something like this? Use PIL to make a "contact sheet" of images?
你有没有这样的事情?使用PIL制作图像的“联系表”?
Perhaps there are others here that are closer to what you want: http://code.activestate.com/recipes/tags/graphics/
也许这里有其他人更接近你想要的东西:http://code.activestate.com/recipes/tags/graphics/
#1
1
Here is a function that wraps the contact sheet function S.Lott mentioned.
这是一个包含S.Lott提到的联系表函数的函数。
#!/usr/bin/env python
import os, os.path
from contactsheet import make_contact_sheet
def make_film_strip(fnames,
(photow,photoh),
(marl,mart,marr,marb),
padding):
return make_contact_sheet(fnames,
(1, len(fnames)),
(photow,photoh),
(marl,mart,marr,marb),
padding)
It is assuming the recipe is saved as contactsheet.py
. Usage is:
假设配方保存为contactsheet.py。用法是:
fstrip = filmstrip.make_film_strip(filmstrip.fnames, (120, 120), (0,0,0,0), 0)
fstrip.save('/path/to/file.format')
Tested.
#2
4
Do you mnean something like this? Use PIL to make a "contact sheet" of images?
你有没有这样的事情?使用PIL制作图像的“联系表”?
Perhaps there are others here that are closer to what you want: http://code.activestate.com/recipes/tags/graphics/
也许这里有其他人更接近你想要的东西:http://code.activestate.com/recipes/tags/graphics/